我們有同樣的需要發佈我們的解決方案到多個文件共享位置,而在幾個月前問這個問題的時候,我認爲一個答案可以讓社區受益。
由於VS發佈配置文件是普通的MSBuild文件,可以很容易地擴展,這裏是我帶來的解決方案。
請注意,我從我們的構建過程中提取了一些代碼片段,它有點複雜,所以我不保證它會在沒有改動的情況下工作。
在發佈配置文件中,我添加了一個自定義DeploymentPaths項目,如下所示。 請注意,您可以定義一個或多個其他位置。
<ItemGroup Label="Defines additional publish locations">
<DeploymentPaths Include="\\SERVER1\ShareFolder\ProjectA\" />
<DeploymentPaths Include="\\SERVER2\ShareFolder\ProjectA\" />
</ItemGroup>
然後,我添加了一個自定義的目標CustomWebFileSystemPublish後WebFileSystemPublish運行。該目標調用另一個MSBuild文件publish.xml,該文件執行刪除現有文件並複製新文件。
<!-- Custom File System Publish to deploy to additional locations based on DeploymentPaths -->
<Target Name="CustomWebFileSystemPublish" AfterTargets="WebFileSystemPublish" Condition=" @(DeploymentPaths)!='' ">
<CreateItem Include="$(MSBuildProjectDirectory)\$(_PackageTempDir)">
<Output ItemName="AbsoluteSourcePathItem" TaskParameter="Include" />
</CreateItem>
<CreateProperty Value="%(AbsoluteSourcePathItem.Fullpath)">
<Output PropertyName="AbsoluteSourcePath" TaskParameter="Value" />
</CreateProperty>
<Message Text="### CustomWebFileSystemPublish" Importance="high" />
<Message Text="### DeploymentPaths: @(DeploymentPaths)" Importance="high" />
<MSBuild Projects="$(MSBuildProjectFile)" Properties="AbsoluteSourcePath=$(AbsoluteSourcePath)" Targets="DoPublish" />
</Target>
<Target Name="DoPublish">
<Message Text="### DoPublish $(AbsoluteOutputPath) | %(DeploymentPaths.Identity)" Importance="normal" />
<!-- Adjust path to the publish.xml file depending on where you put it in your solution -->
<MSBuild Projects="..\Deployment\publish.xml" Properties="OutputPath=$(AbsoluteSourcePath);DeployPath=%(DeploymentPaths.Identity)" />
</Target>
最後,這裏是publish.xml的MSBuild文件
<!-- Publish.xml -->
<Project ToolsVersion="4.0" DefaultTargets="Default" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="Start">
<PropertyGroup>
<!-- Ensure DeployPath has the expected trailing slash -->
<DeployPath Condition=" '$(DeployPath)' != '' and !HasTrailingSlash('$(DeployPath)') ">$(DeployPath)\</DeployPath>
</PropertyGroup>
<Message Text=" # Deploying from $(OutputPath) to $(DeployPath) " Importance="normal" />
</Target>
<Target Name="CleanDeployFolder" DependsOnTargets="Start"
Condition=" $(DeployPath)!=''">
<Message Text=" # Cleaning files in $(DeployPath)" Importance="normal" />
<!-- Defines the files to clean -->
<ItemGroup>
<DeployCleanFiles Include="$(DeployPath)\**\*.*" />
</ItemGroup>
<!--Delete files in Deploy folder (folders not deleted by Delete Task)-->
<Delete Files="@(DeployCleanFiles)" />
<Message Text=" # Cleaning files in $(DeployPath) Completed" Importance="normal" />
</Target>
<Target Name="CopyToDeployFolder" DependsOnTargets="CleanDeployFolder"
Condition=" $(DeployPath)!=''">
<Message Text=" # Copying files to $(DeployPath)" Importance="normal" />
<ItemGroup>
<OutputFiles Include="$(OutputPath)\**\*.*" />
</ItemGroup>
<Copy SourceFiles="@(OutputFiles)" DestinationFolder="$(DeployPath)%(OutputFiles.RecursiveDir)" />
<Message Text=" # Copying files to $(DeployPath) Completed" Importance="normal" />
</Target>
<Target Name="Default" DependsOnTargets="CopyToDeployFolder"
Condition=" $(OutputPath)!='' And $(DeployPath)!='' ">
<Message Text=" # Deploying from $(OutputPath) to $(DeployPath) Completed" Importance="normal" />
</Target>
</Project>
謝謝,我確實有這樣的一記夫婦的小事情,但我真的只是希望以某種方式把它所有的內如果可能,發佈功能和解決方案。但不錯的建議謝謝。 – Cragly