檢查字符串是否不包含URL段並與其匹配

Question

如何檢查URL字符串是否不包含以下字符串：test/test/posts/search/1234567，這樣當我提供以下URL時：test/test/1234567match函數將返回：["test/test/1234567", "test/test/", "", "1234567"]？

更新：

如果我在URL提供/posts/search我想忽略這個表達式中re.test(url)功能。

// var url = "test/test/posts/search/1234567"; // desired result: null 
 
var url = "test/test/1234567"; // result: ["test/test/1234567", "test/test/", undefined, "1234567"] 
 
var urlPrefix = 'test/test/'; 
 
var re = new RegExp('(' + urlPrefix + ')(posts\/search\/)([0-9]+)', 'i'); 
 
console.log(url.match(re));

Answer 1

你就要成功了，你只需要進行第二個捕獲組可選的?量詞意思0或1次出現的，貪婪：

var url = "test/test/posts/search/1234567"; // result: null 
 
var urlPrefix = 'test/test/'; 
 
if (!url.includes("posts/search/")) { 
 
    var re = new RegExp('(' + urlPrefix + ')(posts/search/)?([0-9]+)', 'i'); 
 
    //             ^ 
 
    console.log(url.match(re)); 
 
} 
 
else { 
 
console.log(url + " contains 'posts/search/'!"); 
 
}