需要一些幫助PHP的MySQL

Question

這裏的問題是

$rd = do_mysql_query("SELECT sum(product_price * '{$count}') as letsee 
         FROM prices 
         WHERE product_id = '{$record['prodid']}' 
         AND id='{$id_p}' 
         ORDER BY product_id") or sqlerr(__FILE__, __LINE__); 
while($row = mysqli_fetch_array($rd)){ 
echo "{$record['prodid']}:{$row['letsee']}<br />"; //id:count 
} 

它爲我

10:130 
10:95 
7:88 
6:35 
6:120 
6:330 
11:104 
11:64 

我需要加用ID

所需結果的所有罪名

• 10：225
• 7:88
• 6：485
• 11：168

感謝

Answer 1

您可以用PHP做到這一點：

foreach($records as $record){//First loop or something like it 
    $rd = do_mysql_query("SELECT sum(product_price * '{$count}') as letsee FROM prices WHERE product_id = '{$record['prodid']}' AND id='{$id_p}' ORDER BY product_id") or sqlerr(__FILE__, __LINE__); 
    while($row = mysqli_fetch_array($rd)){ 
     $final_array[$record['prodid']]+=$row['letsee']; //id:count 
    } 
}//End of First loop or something like it 

foreach($final_array as $key => $value){ 
    echo $key.':'.$value; 
} 

注：我認爲你應該使用PHP，因爲檢查你的代碼似乎，你有另一個循環得到$record['prodid']和$count這是造成重複。如果您不止一次發送相同的product_id，則無法使用查詢來解決此問題。

Answer 2

試試這個

$rd = do_mysql_query("SELECT sum(product_price) as letsee FROM prices WHERE product_id = '{$record['prodid']}' AND id='{$id_p}' GROUP BY product_id ORDER BY product_id") or sqlerr(__FILE__, __LINE__); 
while($row = mysqli_fetch_array($rd)){ 
echo "{$record['prodid']}:" . $row['letsee'] * $count ."<br />"; //id:count 
}