XML序列化

Question

我對XML在

<?xml version="1.0" ?> 
<manifest attr="TEXT" attr="TEXT" attr="TEXT"> 
<list name="TRIM"> 
    <feature id="TEXT"/> 
    <feature id="TEXT"/> 
    <feature id="TEXT"/> 
    <feature id="TEXT"/> 
    <feature id="TEXT"/> 
</list> 
<list attr="TEXT"> 
    <feature id="TEXT"/> 
    <feature id="TEXT"/> 
</list> 
<list attr="TEXT"/> 
<list attr="TEXT"> 
    <feature id="TEXT" attr="TEXT"/> 
    <feature id="TEXT" attr="TEXT"/> 
</list> 
</manifest> 

我想這個連載使用C＃和IXmlSerializable接口格式。我有三個類，它們都繼承了IXmlSerializable接口，我的意圖是XML將由最上層的類讀入，並且它將通過將「list」類型的xml傳遞給子對象序列化程序來循環。然後「list」序列化依次循環所有「功能」條目。以下是我的代碼的減少版本。

我已經嘗試了幾種循環方法，但總是以無限循環結束，因嘗試將錯誤類型的xml錯誤位串行化而導致錯誤，或者在跳過整個列表後到達結尾。

我是新來的Xml序列，而這種做法是幼稚的，我願意接受任何建議。

此XML很可能會在將來改變（多個屬性，元素類型等）等等必須維護，我不能保證空元素將不存在任一。

using UnityEngine; 
using System.Collections; 
using System.Xml.Serialization; 

[XmlRoot("partManifest")] 
public class ModelManifest : IEnumerator, IEnumerable, IXmlSerializable { 

    [XmlRoot("feature")] 
    public class Feature : IXmlSerializable 
    { 
     string m_id; 
     string m_description; 

     #region IXmlSerializable implementation 
     System.Xml.Schema.XmlSchema System.Xml.Serialization.IXmlSerializable.GetSchema()  
     { 
      throw new System.NotImplementedException(); 
     } 

     void System.Xml.Serialization.IXmlSerializable.ReadXml (System.Xml.XmlReader reader) 
     {  
     m_id = reader.GetAttribute("id"); 
     } 

     void System.Xml.Serialization.IXmlSerializable.WriteXml (System.Xml.XmlWriter writer) 
     { 
     throw new System.NotImplementedException(); 
     } 
     #endregion 
    } 

    [XmlRoot("feature-list")] 
    public class FeatureList : IXmlSerializable 
    { 
     string m_name; 

     System.Collections.Generic.List<Feature> m_features = new System.Collections.Generic.List<Feature>(); 

     #region IXmlSerializable implementation 
     public System.Xml.Schema.XmlSchema GetSchema() 
     { 
      throw new System.NotImplementedException(); 
     } 

     public void ReadXml (System.Xml.XmlReader reader) 
     {    
      XmlSerializer valueSerializer = new XmlSerializer(typeof(Feature)); 

      // Will return if no features present 
      if(reader.IsEmptyElement) 
       return; 

      reader.ReadStartElement("feature-list"); 
      while(true) 
      { 
       m_features.Add ((Feature)valueSerializer.Deserialize(reader)); 
       i++; 
       bool l_isAnotherSibling = reader.ReadToNextSibling("feature"); 

       if(!l_isAnotherSibling) 
        break; 
      } 
      Debug.Log (i.ToString() + " Features"); 
     } 

     public void WriteXml (System.Xml.XmlWriter writer) 
     { 
      throw new System.NotImplementedException(); 
     } 
     #endregion 
    } 

    System.Collections.Generic.List<FeatureList> m_featureLists = new System.Collections.Generic.List<FeatureList>(); 

    #region IXmlSerializable implementation 
    public System.Xml.Schema.XmlSchema GetSchema() 
    { 
     throw new System.NotImplementedException(); 
    } 

    public void ReadXml (System.Xml.XmlReader reader) 
    {  
     XmlSerializer valueSerializer = new XmlSerializer(typeof(FeatureList)); 

     if(reader.IsEmptyElement) 
      return; 

     reader.ReadStartElement("partManifest"); 

     while (true) 
     {    
      m_featureLists.Add ((FeatureList)valueSerializer.Deserialize(reader)); 

      //bool l_isAnotherSibling = reader.ReadToNextSibling("feature-list"); 

      //if(!l_isAnotherSibling) 
      // break; 
      if(reader.NodeType == System.Xml.XmlNodeType.EndElement) 
       break; 

      if(Input.GetKeyUp(KeyCode.A)) 
       break; 
     } 

     reader.ReadEndElement(); 
    } 

    public void WriteXml (System.Xml.XmlWriter writer) 
    { 
     throw new System.NotImplementedException(); 
    } 
    #endregion 
} 

Answer 1

除非你有一個很好的理由需要實現IXmlSerializable的，我只想用XmlSerializer的和適當的類屬性。

基於給定的XML例子，這應該這樣做。請注意，我必須重命名清單中的兩個attr屬性，因爲具有多個具有相同名稱的屬性是無效的。

using System; 
using System.Collections.Generic; 
using System.Xml; 
using System.Xml.Schema; 
using System.Xml.Serialization; 

[Serializable] 
[XmlRoot("manifest")] 
public class Manifest 
{ 
    [XmlElement("list")] 
    public List<FeatureList> FeatureLists { get; set; } 

    [XmlAttribute("attr")] 
    public string Attr { get; set; } 

    [XmlAttribute("attr2")] 
    public string Attr2 { get; set; } 

    [XmlAttribute("attr3")] 
    public string Attr3 { get; set; } 
} 

[Serializable] 
public class FeatureList 
{ 
    [XmlElement("feature")] 
    public List<Feature> Features { get; set; } 

    [XmlAttribute("name")] 
    public string Name { get; set; } 

    [XmlAttribute("attr")] 
    public string Attr { get; set; } 
} 

[Serializable] 
public class Feature 
{ 
    [XmlAttribute("id")] 
    public string Id { get; set; } 

    [XmlAttribute("attr")] 
    public string Attr { get; set; } 
} 

使用這樣的代碼：

var stream = ... // open the XML 
var serializer = new XmlSerializer(typeof (Manifest)); 
var manifest = (Manifest) serializer.Deserialize(stream);