我一直在使用下面的代碼來獲取我認爲是來自openweathermap API的JSON字符串。爲什麼JSON.parse適用於Google開發人員工具,但不適用於我的js文件?
var request = new XMLHttpRequest();
request.open('GET', 'http://api.openweathermap.org/data/2.5/weather?lat=12&lon=-50&APPID=myKey');
request.send();
var data = JSON.parse(request.responseText);
,當我訪問它的JSON字符串直接是這樣的:
{"coord":{"lon":-50,"lat":12},"weather":[{"id":802,"main":"Clouds","description":"scattered clouds","icon":"03n"}],"base":"stations","main":{"temp":301.461,"pressure":1025.84,"humidity":100,"temp_min":301.461,"temp_max":301.461,"sea_level":1025.82,"grnd_level":1025.84},"wind":{"speed":6.68,"deg":80.5004},"clouds":{"all":32},"dt":1507680994,"sys":{"message":0.0025,"sunrise":1507712963,"sunset":1507755824},"id":0,"name":"","cod":200}
然而,當我使用JSON.parse(request.responseText),我得到一個語法錯誤 - 未捕獲的SyntaxError:意外JSON輸入 結束在JSON.parse()來
但是當我使用解析在Chrome開發者工具,它工作正常,我可以用自己的鑰匙例如訪問值JSON.parse(data)['coord']['lon']
返回-50
在解析之前是否記錄了'request.responseText'來驗證它被提取? – Optional
這是**不是**你如何閱讀** async **操作的響應 – Dummy
可能的重複[如何從異步調用返回響應?](https://stackoverflow.com/questions/14220321/how-do-i-return-the-an-asynchronous-call) – Xufox