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我使用的是OpenJPA 2.2.0，當我執行選擇語句時，出現「列索引超出範圍，0 < 1」的錯誤。獲取列索引超出範圍，0 <1
EntityManager entityMgrObj = emf.getEntityManager();
entityMgrObj.clear();
Query query = entityMgrObj.createNativeQuery("select * from company_user where user_id = 1001);
List<CompanyUserDO> companyUserDOObj = null;
try {
companyUserDOObj = query.getResultList();
} catch (Exception e) {
System.out.println(e.getMessage());
}
當使用Query.getResultList（）執行我得到 「列索引超出範圍，0 < 1」 的錯誤。有人能讓我知道上述代碼中的錯誤嗎？
@UPDATE
當我不明白下面的堆棧異常被打印在控制檯上。
Exception in thread "main" <openjpa-2.2.0-r422266:1244990 fatal general error> org.apache.openjpa.persistence.PersistenceException: Column Index out of range, 0 < 1.
FailedObject: select * from company_user where user_id=1001 [java.lang.String]
at org.apache.openjpa.jdbc.sql.DBDictionary.narrow(DBDictionary.java:4918)
at org.apache.openjpa.jdbc.sql.DBDictionary.newStoreException(DBDictionary.java:4878)
at org.apache.openjpa.jdbc.sql.SQLExceptions.getStore(SQLExceptions.java:136)
at org.apache.openjpa.jdbc.sql.SQLExceptions.getStore(SQLExceptions.java:118)
at org.apache.openjpa.jdbc.sql.SQLExceptions.getStore(SQLExceptions.java:70)
at org.apache.openjpa.jdbc.kernel.GenericResultObjectProvider.handleCheckedException(GenericResultObjectProvider.java:125)
at org.apache.openjpa.lib.rop.EagerResultList.<init>(EagerResultList.java:40)
at org.apache.openjpa.kernel.QueryImpl.toResult(QueryImpl.java:1251)
at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:1007)
at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:863)
at org.apache.openjpa.kernel.QueryImpl.execute(QueryImpl.java:794)
at org.apache.openjpa.kernel.DelegatingQuery.execute(DelegatingQuery.java:542)
at org.apache.openjpa.persistence.QueryImpl.execute(QueryImpl.java:286)
at org.apache.openjpa.persistence.QueryImpl.getResultList(QueryImpl.java:302)
at zumigo.geofence.test.dalTest.main(dalTest.java:62)
Caused by: java.sql.SQLException: Column Index out of range, 0 < 1.
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1073)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:987)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:982)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:927)
at com.mysql.jdbc.ResultSetImpl.checkColumnBounds(ResultSetImpl.java:812)
at com.mysql.jdbc.ResultSetImpl.getStringInternal(ResultSetImpl.java:5651)
at com.mysql.jdbc.ResultSetImpl.getString(ResultSetImpl.java:5570)
at org.apache.commons.dbcp.DelegatingResultSet.getString(DelegatingResultSet.java:213)
at org.apache.commons.dbcp.DelegatingResultSet.getString(DelegatingResultSet.java:213)
at org.apache.openjpa.lib.jdbc.DelegatingResultSet.getString(DelegatingResultSet.java:121)
at org.apache.openjpa.jdbc.sql.DBDictionary.getString(DBDictionary.java:886)
at org.apache.openjpa.jdbc.sql.ResultSetResult.getStringInternal(ResultSetResult.java:474)
at org.apache.openjpa.jdbc.sql.AbstractResult.getString(AbstractResult.java:767)
at org.apache.openjpa.jdbc.meta.strats.StringFieldStrategy.getPrimaryKeyValue(StringFieldStrategy.java:217)
at org.apache.openjpa.jdbc.meta.ClassMapping.getObjectId(ClassMapping.java:188)
at org.apache.openjpa.jdbc.meta.ClassMapping.getObjectId(ClassMapping.java:147)
at org.apache.openjpa.jdbc.kernel.JDBCStoreManager.load(JDBCStoreManager.java:1002)
at org.apache.openjpa.jdbc.kernel.GenericResultObjectProvider.getResultObject(GenericResultObjectProvider.java:93)
at org.apache.openjpa.lib.rop.EagerResultList.<init>(EagerResultList.java:36)
... 8 more
@UPDATE 2 搜索和調試發現persistence.xml文件被指向一箇舊的數據庫，因此這是給上述錯誤之後。
更改了數據庫URL並且應用程序工作正常。 :)
對我來說是「*」：我不知道OpenJPA的，但我的兩分錢是，它試圖通過列名獲取列的索引，但在這種情況下它不能並返回0，這是一個非有效的值。對不起，如果這不能幫助你，但我甚至不是一個真正的開發人員：D –
我不認爲是這種情況，因爲我能執行以下查詢'select * from用戶，其中用戶名如xxx和密碼像yyy' – Natraj