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我可以從Web服務器讀取文本並將其打印到Xcode uilabel,但我不知道如何解析返回陣列。我試圖從服務器獲取A和B,添加它們,並打印使用到的UILabel斯威夫特3.PHP,Xcode 8,Swift 3 - 如何將數組從Web服務器返回到Xcode模擬器
這是PHP和Xcode的8:
連接,add.php
<?php
$a=3;
$b=5;
$data=array($a,$b);
echo json_encode($data);
?>
的Xcode 8
import UIKit
import Foundation
class ViewController: UIViewController {
var a=0
var b=0
var c=0
@IBOutlet weak var result: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a
nib.
}
@IBAction func getVars(_ sender: AnyObject) {
// set label during request
self.result.text="WAITING"
// send request to connect-add.php and retrieve a and b
let myUrl = NSURL(string: "http://www.example.com/connect-add.php")
var request = URLRequest(url:URL(string:
"http://www.example.com/connect-add.php")!)
request.httpMethod = "POST"
let postString = ""
request.httpBody = postString.data(using: .utf8);
let task = URLSession.shared.dataTask(with: request) {
data, response, error in
if error != nil
{
print("error=\(error)")
return
}
// receive response to connect-add and parse to a and b
var response = String(data: data!, encoding: .utf8)
var a=response[0]
var b=response[1]
// add a and b and display
var c=a+b
self.result.text=c
}
task.resume()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
的Xcode給我用於設定一個變種=響應的誤差[0]和用於設置無功b =反應[1]。有任何想法嗎?
我編輯了PHP和Xcode來添加JSON序列化解析。 Xcode顯示一個錯誤 - 使用未解析的標識符「JSON」。這是代碼。
PHP
<?php
$a=3;
$b=5;
$data="a1=".$a.", b1=".$b;
echo json_encode($data);
?>
的Xcode 8
import UIKit
import Foundation
class ViewController: UIViewController {
var a=0
var b=0
var c=0
@IBOutlet weak var result: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a
nib.
}
@IBAction func getVars(_ sender: AnyObject) {
// set label during request
self.result.text="WAITING"
// send request to connect-add.php and retrieve a and b
let myUrl = NSURL(string: "http://www.example.com/connect-add.php")
var request = URLRequest(url:URL(string:
"http://www.example.com/connect-add.php")!)
request.httpMethod = "POST"
let postString = ""
request.httpBody = postString.data(using: .utf8);
let task = URLSession.shared.dataTask(with: request) {
data, response, error in
if error != nil
{
print("error=\(error)")
return
}
// receive response to connect and parse to a and b
var response = String(data: data!, encoding: .utf8)
var obj=JSON.parse(response)
var a=obj.a1
var b=obj.b1
// add a and b and display
var c=a+b
self.result.text=c
}
task.resume()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
你需要看看像'讓JSON =試試? JSONSerialization.jsonObject(with:data)' – cmorrissey
@cmorrissey我加了JSON.parse。它仍然給出一個錯誤 - 使用未解析的標識符「JSON」。 – Aleric