序列化和歸檔對象

Question

我需要做同樣的操作，但在一個流。你能幫我嗎？

public static byte[] archivingAndSerialization(Object object){ 

    ByteArrayOutputStream serializationByteArray = new ByteArrayOutputStream(); 
    ByteArrayOutputStream archvingByteArray = new ByteArrayOutputStream(); 
    try { 

    ObjectOutputStream byteStream = new ObjectOutputStream(serializationByteArray); 
    byteStream.writeObject(object); 
    ZipOutputStream out = new ZipOutputStream(archvingByteArray); 
    out.putNextEntry(new ZipEntry("str")); 
    out.write(serializationByteArray.toByteArray()); 
    out.flush(); 
    out.close(); 

    } catch (IOException e) { 
logger.error("Error while IOException!", e); 
    } 
    return archvingByteArray.toByteArray(); 
} 

Answer 1

嘗試

ByteArrayOutputStream baos = new ByteArrayOutputStream(); 
ObjectOutputStream oos= new ObjectOutputStream(new DeflatingOutputStream(baos)); 
oos.writeObject(object); 
oos.close(); 
return baos.toByteArray(); 

注：除非對象是中等大小，壓縮它將使更大，因爲它添加一個頭。 ;）

反序列化

ObjectInputStream ois = new ObjectInputStream(
    new InflatorInputStream(new ByteArrayInputStream(bytes))); 
return ois.readObject();