我在使用javascript的window.open在Internet Explorer中看到「無效參數」。我將如何解決它?我在「var newwindow = window.open(url,'Popup Demo','toolbar = no,location = no,directories = no,status = no,menubar = no, scrollbars = no,resizable = no,copyhistory = no,width ='+ w +',height ='+ h +',top ='+ top +',left ='+ left);「。IE上的window.open錯誤?
這裏是我的代碼:
<script type="text/javascript" language="javascript">
<!--
function popitup(url) {
var w = 500;
var h = 500;
var left = (screen.width/2)-(w/2);
var top = (screen.height/2)-(h/2);
var newwindow = window.open (url, 'Popup Demo', 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
if (window.focus) {
newwindow.focus();
}
return false;
}
// -->
</script>
爲什麼你有「不要在Netscape 2時代瀏覽器中將此腳本呈現爲文本」的評論?沒有人使用Netscape 2時代瀏覽器。 – Quentin