我試圖編寫一個應用程序，它從本地xml文件中讀取，並且需要一些幫助。我已經閱讀了這裏的一些文章以及google和youtube來讀取/寫入xml文件，但其中大部分文件都是在線文件。我正在尋找在Android本地讀/寫xml。到目前爲止，我認爲，我需要的步驟如下。在Android本地讀取XML
我似乎無法得到第一個2的工作。我不是在尋找代碼，也不是尋找代碼的簡單方法。我真的想弄清楚這一點，但需要你們大家在這裏的一些指導。我真的無法找到一種方法來讀取XML文件。從我在這裏找到的，我需要將XML文件放在res/raw文件夾中，然後從那裏，我不太確定該怎麼做。我如何將它讀入數組？一旦我把這個東西運行起來，我會盡我所能發佈代碼，並希望幫助其他有類似問題的人。再次感謝！
我終於得到它的工作就是我想要的，這裏是我試圖完成。對所有提供的答案，非常感謝！我拿走了你的每一個模式，並根據需要定製它。我絕不是一個android/java/xml專家，但這是我得到的，它的工作方式我想要！
public class MainActivity extends Activity {
Spinner spinner;
List<String> ingredient = new ArrayList<String>();
List<String> effect1 = new ArrayList<String>();
List<String> effect2 = new ArrayList<String>();
List<String> effect3 = new ArrayList<String>();
List<String> effect4 = new ArrayList<String>();
XmlResourceParser myXml;
int eventType;
String nodeValue;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
loadXml(); // Reads XML and loads it into Lists, One list for each element
convertListToSpinner(); // Takes Lists and merges data with Spinners (Currently Unimplemented)
}
private void convertListToSpinner() {
// TODO Auto-generated method stub
}
private void loadXml() {
// TODO Auto-generated method stub
myXml = getBaseContext().getResources().getXml(R.xml.xmlfilename);
try {
myXml.next();
eventType = myXml.getEventType(); // Get current xml Event
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
while(eventType != XmlPullParser.END_DOCUMENT){
if(eventType == XmlPullParser.START_DOCUMENT){
// checks can be placed here to make sure file is read
}
else if(eventType == XmlPullParser.START_TAG){
nodeValue = myXml.getName();
try{
if(nodeValue.equalsIgnoreCase("Ingredient")){ //Finds Ingredient tag
myXml.next(); //Since the ingredient tag does not hold the text, we go to next element area
ingredient.add(myXml.getText().trim()); // Set the text of the Ingredient tag to list
}
//Since the effect tags are followed by ending tags, we can just do nextText() to get tag text
if(nodeValue.equalsIgnoreCase("Effect1")){
effect1.add(myXml.nextText().trim()); // Set the text of the Effect1 tag to list
}
if(nodeValue.equalsIgnoreCase("Effect2")){
effect2.add(myXml.nextText().trim()); // ditto
}
if(nodeValue.equalsIgnoreCase("Effect3")){
effect3.add(myXml.nextText().trim()); // ditto
}
if(nodeValue.equalsIgnoreCase("Effect4")){
effect4.add(myXml.nextText().trim()); // ditto
}
}catch(Exception e){
e.getMessage();
}
}
try {
eventType = myXml.next();
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
for(int i = 0; ingredient.size() > i; i++){
System.out.println(ingredient.get(i));
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
}
而XML文件是以當前格式。
<?xml version="1.0" encoding="UTF-8"?>
<resources xmlns:android="http://schemas.android.com/apk/res/android" >
<item
name="item"
type="string">
<Ingredient>
Intrests
<effect1>
Android
</effect1>
<effect2>
Programming
</effect2>
<effect3>
Type O Negative
</effect3>
<effect4>
Sirenia
</effect4>
</Ingredient>
<Ingredient>
Virtues
<effect1>
Power
</effect1>
<effect2>
Money
</effect2>
<effect3>
Knowledge
</effect3>
<effect4>
Kindness
</effect4>
</Ingredient>
</item>
</resources>
我希望這可以幫助其他有類似問題的人。再次感謝Sobo和HADEV的貢獻！
我敢肯定有做的是做什麼工作的一種更好的方式，但我很高興我得到了這個工作:)
在主類
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.Toast;
public class SimpleList extends Activity { //SimpleList is the name of this class
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
final ListView lv=(ListView)findViewById(R.id.listView1);
//final ArrayList<String> myNewList = new ArrayList<String>();
ArrayAdapter<CharSequence> adapter=ArrayAdapter.createFromResource(this, R.array.simple_array,android.R.layout.simple_list_item_1);
lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {
// TODO Auto-generated method stub
String item=lv.getItemAtPosition(arg2).toString();
String itemordered;
itemordered = item + " added to list";
Toast.makeText(getApplicationContext(), itemordered, Toast.LENGTH_LONG).show();
}
});
}
}
創建的strings.xml一個字符串數組
<resources>
<string name="app_name">SimpleList</string>
<string name="menu_settings">Settings</string>
<string name="title_activity_main">SimpleList</string>
<string-array name="simple_array">
<item>Bacon Double Cheese Burger</item>
<item>Bacon Cheeses Burger</item>
<item>Cheese Burger</item>
<item>Hamburger</item>
<item>Grilled Chicken Sandwich</item>
<item>Crispy Chicken Sandwich</item>
<item>Chicken Strips</item>
<item>Hot Dog</item>
<item>Chocolate Chip Cookie Dough Polar Swirl</item>
<item>Vanilla Shake</item>
<item>Chocolate Shake</item>
<item>Strawberry Shake</item>
</string-array>
</resources>
main.xml中創建您的ListView佈局
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<ListView
android:id="@+id/listView1"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:divider="#FFCC00"
android:dividerHeight="2dp" >
</ListView>
</LinearLayout>
哇，謝謝你的時間和信息。肯定有幫助！ – 2012-07-21 01:09:47
可以使用SAX解析器
種SAX回調方法：
startDocument（）和調用endDocument（） - 調用的方法在XML文檔的開始和結束。 startElement（）和endElement（） - 在文檔元素的開始和結束處調用的方法。 characters（） - 使用XML文檔元素的開始和結束標記之間的文本內容調用的方法。
假設你有這樣的XML文件：解析
<?xml version="1.0"?>
<company>
<staff>
<firstname>yong</firstname>
<lastname>mook kim</lastname>
<nickname>mkyong</nickname>
<salary>100000</salary>
</staff>
<staff>
<firstname>low</firstname>
<lastname>yin fong</lastname>
<nickname>fong fong</nickname>
<salary>200000</salary>
</staff>
</company>
java類：
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
public class ReadXMLFile {
public static void main(String argv[]) {
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();
DefaultHandler handler = new DefaultHandler() {
boolean bfname = false;
boolean blname = false;
boolean bnname = false;
boolean bsalary = false;
public void startElement(String uri, String localName,String qName,
Attributes attributes) throws SAXException {
System.out.println("Start Element :" + qName);
if (qName.equalsIgnoreCase("FIRSTNAME")) {
bfname = true;
}
if (qName.equalsIgnoreCase("LASTNAME")) {
blname = true;
}
if (qName.equalsIgnoreCase("NICKNAME")) {
bnname = true;
}
if (qName.equalsIgnoreCase("SALARY")) {
bsalary = true;
}
}
public void endElement(String uri, String localName,
String qName) throws SAXException {
System.out.println("End Element :" + qName);
}
public void characters(char ch[], int start, int length) throws SAXException {
if (bfname) {
System.out.println("First Name : " + new String(ch, start, length));
bfname = false;
}
if (blname) {
System.out.println("Last Name : " + new String(ch, start, length));
blname = false;
}
if (bnname) {
System.out.println("Nick Name : " + new String(ch, start, length));
bnname = false;
}
if (bsalary) {
System.out.println("Salary : " + new String(ch, start, length));
bsalary = false;
}
}
};
saxParser.parse("c:\\file.xml", handler);
} catch (Exception e) {
e.printStackTrace();
}
}
}
這可以幫助你http://stackoverflow.com/questions/2728064/parsing-local-xml-file-sax-in-android – HADEV 2012-07-21 01:02:03