過程的InputStream沒有返回過程輸入（OSX）

Question

我試圖得到一個過程中，我推出使用進程生成但是輸出似乎看起來像是從AppleScript的東西，而不是過程的實際輸出的輸出：

代碼：

public static void main(String[] args) { 
    System.out.println(getJavaOutput()); 
} 

public static String getJavaOutput() { 
    try { 
     //kill -9 $(ps -p $PPID -o ppid=) 
     String output = ""; 
     ProcessBuilder macBuilder = new ProcessBuilder("osascript", "-e", 
       "tell application \"Terminal\" to do script \"jps -lV && exit\""); 
     Process p2 = macBuilder.start(); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(p2.getInputStream())); 
     String line; 
     while((line = reader.readLine()) != null){ 
      output += line + System.getProperty("line.separator"); 
     } 
     return output; 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    return null; 
} 

預期輸出：

2680 sun.tools.jps.Jps 
1289 

實際輸出：

tab 1 of window id 742 

Answer 1

你的方法更改爲：

public static String getJavaOutput() { 
    try { 
     String output = ""; 
     ProcessBuilder macBuilder = new ProcessBuilder("/bin/bash", "-c", "jps -lV && exit"); 
     Process p2 = macBuilder.start(); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(p2.getInputStream())); 
     String line; 
     while ((line = reader.readLine()) != null) { 
      output += line + System.getProperty("line.separator"); 
     } 
     return output; 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    return null; 
}