PHP COUNT_RECURSIVE只計算非數組值？

Question

我有一個多維數組的$doclist['area']['source'][#]['type']

調我想獲得一些非空的['type'] = "title"所有條目。

有沒有簡單的方法呢？

雖然我在這裏，有沒有辦法讓['type'] = "title"和['area'] = "something"的所有條目都不是空的？

Answer 1

假設由'area'和'source'你的意思是任意的字符串，你可以窩幾個圈，像這樣：

$num_titles = 0; 
foreach ($doclist as $area => $arr1) { 
    foreach ($arr1 as $source => $arr2) { 
     foreach ($arr2 as $k => $arr3) { 
      if (isset($arr3['title']) && strlen(trim($arr3['title']))) 
       $num_titles++; 
     } 
    } 
} 
print "Titles: {$num_titles}\n"; 
print "Areas: " . sizeof($doclist) . "\n"; 

Answer 2

下面是我寫的基於rfausak的響應函數：我想

function countdocs($arr,$x="",$y="") { 
     if (($x) && ($y)) { 
      return count($arr[$x][$y]); 
     } else if ($x) { 
      $r=0; 
      foreach ($arr[$x] as $arr1) { 
       $r+=count($arr1); 
      } 
      return $r; 
     } else { 
      $r=0; 
      foreach ($arr as $arr1) { 
       foreach ($arr1 as $arr2) { 
        $r+=count($arr2); 
       } 
      } 
      return $r; 
     } 
    } 

有人會覺得它有用。

Answer 3

$ships = array(
    "Passenger ship" => 
     array("Yacht", "Liner", "Ferry"), 
    "War ship" => 
     array("Battle-wagon", "Submarine", "Cruiser"), 
    "Freight ship" => 
     array("Tank vessel", "Dry-cargo ship", "Container 
     cargo ship") 
); 

function myCount($var, $i = 0){ 
    $cnt = 0; 
    foreach ($var as $v) { 
     if (is_array($v) and $i) 
      $cnt += myCount($v, 0); 
     $cnt++; 
    } 
    return $cnt; 
} 
echo myCount($ships, 1);