在MySQL服務器上重新連接已離去

Question

如何修改此類以捕獲MySQL服務器走開的異常並重新連接？

<?php 
class DBConn 
{ 
private $conn; 

public function __construct($persistent = false) 
{ 
    try 
    { 
     $this->conn = new PDO("mysql:host=localhost;dbname=test", 'test', "hoollaahaoo"); 
     $this->conn->exec("SET CHARACTER SET utf8"); 
     $this->conn->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC); 
     if ($persistent) 
      $this->conn->setAttribute(PDO::ATTR_PERSISTENT, true); 
    } 
    catch(PDOException $e) 
    { 
     return $e->getMessage(); 
    } 
} 

public function getConn() 
{ 
    return $this->conn; 
} 
} 

Answer 1

你可能會需要讓自己的類像這樣的

1. 從__construct
2. 刪除try/except然後連接到您DB這樣的：

$conn = null; 
$limit = 10; 
$counter = 0; 
while (true) { 
    try { 
    $conn = DBConn(); 
    break; 
    } 
    catch (Exception $e) { 
    $conn = null; 
    $counter++; 
    if ($counter == $limit) 
     throw $e; 
    } 

}

編輯1：

，但如果你說你的服務器消失了....然後可能是水木清華像槍的脖子的這個

protected function _connect($persistent = false) { 
$conn = null; 
$limit = 10; 
$counter = 0; 
while (true) { 
    try { 
     $this->conn = new PDO("mysql:host=localhost;dbname=test", 'test', "hoollaahaoo"); 
     $this->conn->exec("SET CHARACTER SET utf8"); 
     $this->conn->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC); 
     if ($persistent) 
      $this->conn->setAttribute(PDO::ATTR_PERSISTENT, true); 
} 
    catch (Exception $e) { 
    $conn = null; 
    $counter++; 
    if ($counter == $limit) 
     throw $e; 
    } 
} 

public function __construct($persistent = false) 
{ 
    $this->_connect($persistent); 
}