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所以我試圖執行一個while循環爲數據庫時提交的值爲actual_quote和海報,當它有這些值它張貼div在那些值被顯示,並且對於每一行,爲該單行放置一個新的div。 我不知道該怎麼辦,有什麼幫助?雖然循環爲數據庫時提交的值發佈到div
<div class="wrapper">
<?php $db_name = 'submissions';
$db_user = 'root';
$db_pass = '';
$db_host = 'localhost';
mysql_connect("localhost", $db_user, $db_pass) or die(mysql_error());
mysql_select_db("submissions") or die(mysql_error());
我試圖從這裏開始的,而循環
while($info = mysql_fetch_array($actual_quote, $poster))
{
echo"
<div class="submissions">
<div class="logo-logo"><h2>Questions.</h2>
<div class="checkboxes"><?= !empty($_GET['x']) ? $_GET['x'] : '' ?>
</div>
</div>
<?php
$actual_quote = mysql_query("SELECT actual_quote FROM data");
$info = mysql_fetch_array($actual_quote);
?>
<div class="top-submit">
<?php echo '“' . $info['actual_quote'] . '”'; ?>
</div>
<?php
$poster = mysql_query("SELECT poster FROM data");
$info = mysql_fetch_array($poster);
?>
<div class="poster"><?php echo '-' . $info['poster']; ?>
<div class = "like">
<a href = "javascript:countClicksLike();" class = "btn btn-large" style = "color:green;">Like</a>
<p id = "like" style = "color:green;">0</p>
</div>
<div class = "dislike">
<a href = "javascript:countClicks();" class = "btn btn-large" style = "float:right; color:red;">Dislike</a>
<p id = "dis" style = "color:red;">0</p>
</div>
</div>
<!-- use select to get the items to stay on the page-->
</div>
</div>"
}
?>
但我完全失去了。有什麼建議麼?