PHP如何在提交

Question

後以複選框（交換機）的形式檢查複選框（交換機）的狀態，如何在提交後檢查交換機的狀態以更新MySQL？謝謝

因此，MySQL表不會改變。

從複選框，並提交

<form method="POST" action="process.php"> 
<label class="mdl-switch mdl-js-switch mdl-js-ripple-effect" for="switch-1"> 
<input type="checkbox" id="switch-1" class="mdl-switch__input" checked> 
<span class="mdl-switch__label">Autenticazione a due fattori</span> 
</label> 
.... 
<input onclick="conferma();" class="mdl-button mdl-js-button 
mdl-button--raised mdl-js-ripple-effect mdl-button--accent" type="submit" 
value="Salva" name="submitBtn"> 
</form> 

開關控制和MySQL更新（process.php）

<?php 
session_start(); 
mysql_connect(localhost) or die(mysql_error()); 
mysql_select_db("*******") or die(mysql_error()); 
$user = $_SESSION['users']; 
if(isset($_POST['submitBtn'])) { //form submission occured 
    if(!isset($_POST['switch-1'])){    
     $sql = "UPDATE `*******`.`login_users` SET `auth` = \'checked\' WHERE username = '$user'"; 
     header("location: https://*******.php"); 
    } else { 
     $sql = "UPDATE `*******`.`login_users` SET `auth` = \'unchecked\' WHERE username = '$user'"; 
     header("location: https://*******.php"); 
    } 
} 

?> 

Answer 1

1）修改形式

<form method="POST" action="process.php"> 

    <label class="mdl-switch mdl-js-switch mdl-js-ripple-effect" for="switch-1"> 
    <input type="checkbox" name="switch-1" id="switch-1" class="mdl-switch__input" checked> 
    <span class="mdl-switch__label">Autenticazione a due fattori</span> 
    </label> 
    .... 
    <input type="submit" value="Salva" name="submitBtn" class="mdl-button mdl-js-button 
    mdl-button--raised mdl-js-ripple-effect mdl-button--accent" > 

</form> 

2）創建一個新的process.php頁面在同一個工作目錄中並添加這些。

編輯：

<?php 

session_start(); 
$user = $_SESSION['users']; 

$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "YourDBName"; 

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 

if(isset($_POST['submitBtn'])) { //form submission occured 

    if(isset($_POST['switch-1'])){      
     $sql = "UPDATE login_users SET auth = 'checked' WHERE username = '$user'"; 
    } else { 
     $sql = "UPDATE login_users SET auth = 'no' WHERE username = '$user'"; 
    } 

    if ($conn->query($sql)) { 
     echo "Updated successfully"; 
    } else { 
     echo "Error: " . $sql . "<br>" . $conn->error; 
    } 

} else { 
    echo "Form Submission Error"; 
} 

$conn->close(); 
?> 

希望這是有幫助的。