在PDO/PHP代碼中的未知錯誤

-1

我正在嘗試使用PDO/PHP來顯示數據並將數據插入到使用MySQL的數據庫中。代碼的顯示部件工作正常，但每當我嘗試插入數據我得到這個錯誤：在PDO/PHP代碼中的未知錯誤

SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens

這裏是我的代碼：

<?php 
    $number = 1; 
include 'connection.php'; 

try { 
    $conec = new Connection(); 
    $con = $conec -> Open(); 
    if ($con) { 
     $sql1 = "SELECT company_name FROM test_corp WHERE company_num = $number"; 
     $stmt1 = $con->query($sql1); 
     $row = $stmt1->fetchObject(); 
     $company_name = $row->company_name; 
     if (isset($company_name)) { 

     } else { 
      echo "error: memory location not set."; 
     } 

     $sql2 = "SELECT company_abb FROM test_corp WHERE company_num = $number"; 
     $stmt2 = $con->query($sql2); 
     $row = $stmt2->fetchObject(); 
     $company_abb = $row->company_abb; 
     if (isset($company_abb)) { 

     } else { 
      echo "error: memory location not set."; 
     } 

     $sql3 = "SELECT company_price FROM test_corp WHERE  company_num = $number"; 
     $stmt3 = $con->query($sql3); 
     $row = $stmt3->fetchObject(); 
     $company_price = $row->company_price; 
     if (isset($company_price)) { 

     } else { 
      echo "error: memory location not set."; 
     } 

     $sql4 = "SELECT investor_username FROM test_corp WHERE company_num = $number"; 
     $stmt4 = $con->query($sql4); 
     $row = $stmt4->fetchObject(); 
     $Sample_Investor1 = $row->investor_username; 
     if (isset($Sample_Investor1)) { 

     } else { 
      echo "error: memory location not set."; 
     } 

     $sql5 = "SELECT investor_amount FROM test_corp WHERE company_num = $number"; 
     $stmt5 = $con->query($sql5); 
     $row = $stmt5->fetchObject(); 
     $Sample_Investor1_Amount = $row->investor_amount; 
     if (isset($Sample_Investor1_Amount)) { 

     } else { 
      echo "error: memory location not set."; 
     } 



     if (isset($_POST['Buy_Dollar'])) { 
      $Buy_Dollar = $_POST['Buy_Dollar']; 
     } 

     $total = 100; 

     $query7 = "INSERT INTO test_corp (company_name, company_abb,company_price, investor_name, investor_username, investor_amount, total, company_num) VALUES (:insert_value1, :insert_value2,:insert_value3, :insert_value4, :insert_value5, :insert_value6, :insert_value7, insert_value8)"; 
     $stmt7 = $con->prepare($query7); 

     $stmt7->bindParam(':insert_value1', $company_name); 
     $stmt7->bindParam(':insert_value2', $company_abb); 
     $stmt7->bindParam(':insert_value3', $company_price); 
     $stmt7->bindParam(':insert_value4', $investor_name); 
     $stmt7->bindParam(':insert_value5', $investor_username); 
     $stmt7->bindParam(':insert_value6', $Buy_Dollar); 
     $stmt7->bindParam(':insert_value7', $total); 
     $stmt7->bindParam(':insert_value8', $number); 
     $stmt7->execute(); 
    } else { 
     echo $con; 
    } 
} 
catch (PDOException $ex) { 
    echo $ex -> getMessage(); 
} 
    ?>

來源

2017-07-07 jdw136

你是什麼意思不明錯誤？ –

缺少一些東西 - >'insert_value8）' –

'insert_value8'有一個冒號缺失。它應該是'：insert_value8' –

$query7 = "INSERT INTO test_corp (company_name, company_abb,company_price, investor_name, investor_username, investor_amount, total, company_num) VALUES (:insert_value1, :insert_value2,:insert_value3, :insert_value4, :insert_value5, :insert_value6, :insert_value7, insert_value8)";

你insert_value8錯過:：d

來源

2017-07-07 14:33:34 WilsonNG

在PDO/PHP代碼中的未知錯誤

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