正則表達式在文本中查找目錄

Question

如何在文本塊中查找路徑和文件名？

您標記這是重複之前，我知道有關文件路徑的問題存在

• Regex for parsing directory and filename（不段落相匹配。）
• Regex that matches directory path excluding filepath（這只是一個相匹配的文件名，答案不段落的工作，並沒有解決.或空格）
• java regular expression to match file path（不涉及.或空格）
• Regex for extracting filename from path（不涉及段落是）

例如

In file included from /some/directoy/3.33A.37.2/something else/dogs.txt, 
       from /some/directoy/something else/dogs.txt, 
       from /some/directoyr/3.33A.37.2/something else/dogs.txt, 
       from /var/log/xyz/10032008.log, 
       from /var/log/xyz/test.c:29: 
Solution: 
please the file something.h has to be alone without others include, it has to be present in release letter, 
in order to be included in /var/log/xyz/test.c and /var/log/xyz/test.h automatically 
Other Note: 
The file something.c must contain the somethinge.h and not the ecpfmbsd.h because it doesn't contain C operative code.. everything good.. 

以下是理想的匹配：

/some/directoy/3.33A.37.2/something else/dogs.txt 
/some/directoy/something else/dogs.txt 
/some/directoyr/3.33A.37.2/something else/dogs.txt 
/var/log/xyz/10032008.log 
/var/log/xyz/test.c:29 (this is a tricky one, ok with out it) 
/var/log/xyz/test.c 
/var/log/xyz/test.h 

進一步說，如果我找到什麼答案怎麼能我更改它與\而不是/目錄

Answer 1

您可以使用正則表達式是這樣的：

\/.*\.[\w:]+ 

Working demo

順便說一句，如果你想允許路徑反斜槓，你可以有：

[\\\/].*\.[\w:]+ 

Answer 2

這看起來工作：

\/[^,:]*\.\w+

請參閱demo。

如果您知道確切的擴展名，它們的長度以及它們具有的字符，則可以對其進行微調。至於我，\w+會匹配擴展名。