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我正在嘗試使用他們的php library將我的應用程序與SendGrid API documentation集成。Sendgrid API與Symfony2集成
我安裝了它使用的作曲家(composer.json)
"require": {
...
"sendgrid/sendgrid": "2.0.5",
"sendgrid/php-http-client": "3.4"
}
創建服務(services.yml):
sendgrid_service:
class: AppBundle\Services\SendGridApiIntegration
arguments: ['%sendgrid_api_key%', '%sendgrid_api_user%']
服務:
<?php
namespace AppBundle\Services;
use SendGrid;
class SendGridApiIntegration
{
private $api_key;
private $api_user;
public function __construct($api_user, $api_key)
{
$this->api_user = $api_user;
$this->api_key = $api_key;
}
public function testSendGrid()
{
// \SendGrid::register_autoloader();
// $sg = new \SendGrid($this->api_user, $this->api_key);
$sg = new \SendGrid($this->api_key);
$request_body = json_decode('{
"name": "pet",
"type": "text"
}');
$response = $sg->client->contactdb()->custom_fields()->post($request_body);
echo $response->statusCode();
echo $response->body();
echo $response->headers();
}
}
我得到以下錯誤:
Notice: Undefined property: SendGrid::$client
我無法工作,不知道下一步該怎麼做。
在此先感謝