將C＃JSON字符串添加到Web API

Question

當在C＃中創建JSON字符串並嘗試使用WebClient將其發送到Web API時，正面臨一個問題。

目前我有幾個方法，首先是一個工作。使用郵差通過發送文本以下數據集的API正常工作：

郵差數據集 - 這部作品在郵差

{ "record": 
    { 
     "form_id": "efe4f66f-b57c-4497-a370-25c0f3d8746a", 
     "status": "240", 
     "latitude": -82.638039, 
     "longitude": 27.770787, 
     "form_values": 
     { 
      "833b": "99999", 
      "683b": "9999999", 
      "fa37": "Testing", 
      "b2e3": "Testing" 
     } 
    } 
} 

在C＃中，我使用幾種不同的方法來構建這個刺幾乎沒有成功。

C＃列表方法 - Newtonsoft.Json.Serialization

首先是建立一個列表，然後使用Newtonsoft.Json發揮它：

List<Parent> DataList = new List<Parent>(); 
    List<Child> Form = new List<Child.formvalues>(); 
    var Formvals = new Child.formvalues 
    { 
     ActionDescription = Row.ActionDescription, 
     ActionNotes = Row.ActionNotes, 
     ActionID = Row.ActionID, 
     AssetID = Row.AssetID 
    }; 
    Form.Add(Formvals); 

    var DataElement = new Parent 
    { 
     form_id = AppFormID, 
     latitude = Lat, 
     longitude = Long, 
     status = Row.Status, 
     form_values = Form 
    }; 
    DataList.Add(DataElement); 

    string json = JsonConvert.SerializeObject(DataList.ToArray()); 

在此代碼的結果以下字符串：

[ 
    {\"form_id\":\"efe4f66f-b57c-4497-a370-25c0f3d8746a\", 
    \"latitude\":-82.638039, 
    \"longitude\":27.770787, 
    \"status\":239, 
    \"form_values\":[ 
     {\"833b\":99999, 
     \"683b\":9999999, 
     \"fa37\":\"Testing\", 
     \"b2e3\":\"Testing\" 
     }] 
    } 
] 

我嘗試的另一個嘗試是followi NG，這在我看來是最接近至今：

C＃ - 字符串構建方法

string Content = @"{ " 
     + "\"record\": {" 
     + "\"form_id\": "\"" + AppFormID + ""\"," 
     + "\"status\": "\"" + Row.Status + ""\"," 
     + "\"latitude\": "+ Lat + "," 
     + "\"longitude\": "+ Long + "," 
     + "\"form_values\": {" 
      + "\"833b\": "\""+Row.AssetID +""\"," 
      + "\"683b\": "\""+Row.ActionID + ""\"," 
      + "\"fa37\": "\""+Row.ActionDescription + ""\"," 
      + "\"b2e3\": "\""+Row.ActionNotes + ""\"" 
     + "}" 
     + "}" 
     + "}"; 

在該行的結果：

{ \"record\": 
    { 
     \"form_id\": \"efe4f66f-b57c-4497-a370-25c0f3d8746a\", 
     \"status\": \"239\", 
     \"latitude\": -82.638039, 
     \"longitude\": 27.770787, 
     \"form_values\": 
     { 
      \"833b\": \"99999\", 
      \"683b\": \"9999999\", 
      \"fa37\": \"Testing\", 
      \"b2e3\": \"Testing\" 
     } 
    } 
} 

的問題！

所以現在的問題，是有人能夠幫助我實現我投入郵差正好第一JSON格式？

更新 - 6:40 PM

Web客戶端代碼的C＃ AppURLRef在代碼中設置進一步上漲，似乎是在調試器中正確。 json是測試的結果。更新

"[{\"record\":{\"form_id\":\"efe4f66f-b57c-4497-a370-25c0f3d8746a\", 
\"latitude\":-82.638039, 
\"longitude\":27.770787, 
\"status\":\"240\", 
\"form_values\":   
[{\"833b\":\"99999\", 
\"683b\":\"9999999\", 
\"fa37\":\"Testing\", 
\"b2e3\":\"Testing\"}]}}]" 

Answer 1

我會嘗試以下以及NewtonSoft.JSON。

var data = new 
{ 
    record = new 
    { 
     form_id = "efe4f66f-b57c-4497-a370-25c0f3d8746a", 
     status = "240", 
     latitude = -82.638039, 
     longitude = 27.770787, 
     form_values = new Dictionary<string, string>(); 
    } 
} 

data.record.form_values["833b"] = "99999"; 
data.record.form_values["683b"] = "9999999"; 
data.record.form_values["fa37"] = "Testing"; 
data.record.form_values["b2e3"] = "Testing"; 

然後得到的JSON：

string json = JsonConvert.SerializeObject(data); 

Answer 2

的

var http = new WebClient(); 
http.Headers.Add(HttpRequestHeader.ContentType, "application/json"); 
var response = http.UploadString(AppURLRef, "POST", json); 

結果，我認爲這是很相似this One。您可以嘗試以下代碼以滿足要求：

var dd = { 
"FirstName": "ABC", 
"username": "abc123", 
"password": "abc@123", 
"Cnumbers": [{ 
    "Home": "0987654321" 
}, { 
    "Company": "7654321" 
}] 
} 

Answer 3

請嘗試以下操作。

public class Record 
{ 
    [JsonProperty(PropertyName = "form_id")] 
    public string FormId { get; set; } 

    [JsonProperty(PropertyName = "status")] 
    public string Status { get; set; } 

    [JsonProperty(PropertyName = "latitude")] 
    public decimal Latitude { get; set; } 

    [JsonProperty(PropertyName = "longitude")] 
    public decimal Longitude { get; set; } 

    [JsonProperty(PropertyName = "form_values")] 
    public Dictionary<string, string> FormValues { get; set; } 
} 

public class RecordContainer 
{ 
    [JsonProperty(PropertyName = "record")] 
    public Record Record { get; set; } 
} 

用法：

var container = new RecordContainer(); 
container.Record = new Record(); 
// Code to populate values 
JsonConvert.SerializeObject(container); 

我使用Newtonsoft的Json序列化，我得到你已經問相同的輸出。