ongr-io彈性搜索綁定實現與教條symfony2

Question

在我們的symfony2項目中，我們希望使用ongr-io綁定來實現elasticsearch，但是我們的整個系統是建立在教義上的。是否有可能以某種方式使用ongr-io elasticsearch bundle而不用完全重做整個數據庫而不是實體的文檔？

實體，我想指數（搜索領域將是：姓名，ChildCategory和ParentCategory）：

/** 
* Course 
* 
* @ORM\Table(name="course") 
* @ORM\Entity(repositoryClass="CoreBundle\Repository\CourseRepository") 
* @ORM\HasLifecycleCallbacks 
*/ 
    class Course 
    { 
     /** 
     * @var int 
     * 
     * @ORM\Column(name="id", type="integer") 
     * @ORM\Id 
     * @ORM\GeneratedValue(strategy="AUTO") 
     */ 
     private $id; 

     /** 
     * @var string 
     * 
     * @ORM\Column(name="name", type="string", length=255, unique=false) 
     */ 
     private $name; 

     /** 
     * @var ParentCategory 
     * 
     * @ORM\ManyToOne(targetEntity="ParentCategory") 
     * @ORM\JoinColumn(name="parentCategory_id", referencedColumnName="id") 
     */ 
     private $parentCategory; 

     /** 
     * @var ChildCategory 
     * 
     * @ORM\ManyToOne(targetEntity="ChildCategory", inversedBy="courses") 
     * @ORM\JoinColumn(name="childCategory_id", referencedColumnName="id") 
     */ 
     private $childCategory; 

     /** 
     * @var City 
     * 
     * @ORM\ManyToOne(targetEntity="City") 
     * @ORM\JoinColumn(name="city_id", referencedColumnName="id") 
     */ 
     private $city; 

     /** 
     * @var Users 
     * 
     * @ORM\ManyToOne(targetEntity="UserBundle\Entity\Users", inversedBy="course") 
     * @ORM\JoinColumn(name="owner_id", referencedColumnName="id") 
     */ 
     private $owner; 

     /** 
     * @var text 
     * 
     * @ORM\Column(name="description", type="text") 
     */ 
     private $description; 

     /** 
     * @var Picture 
     * 
     * @ORM\OneToMany(targetEntity="CoreBundle\Entity\Picture", mappedBy="course", cascade={"persist", "remove"}) 
     */ 
     private $pictures; 

     /** 
     * @var Ratings 
     * 
     * @ORM\OneToMany(targetEntity="CoreBundle\Entity\Ratings", mappedBy="courseid") 
     */ 
     private $ratings; 

     public $avgRating; 
    } 

Answer 1

這是非常有趣的。

第一件事是實體的位置。 ElasticsearchBundle的文檔必須位於Document目錄中。沒什麼大不了的。您只需要創建一個空類並使用@Document註釋擴展實體。接下來是領域。隨着name領域沒有任何問題，只需添加@property註釋，你很好。更有趣的是與關係。我的建議是創建單獨的屬性和來自該字段關係的getter返回值。我希望你明白了。

更新：

下面是文檔的例子：

的appbundle /實體/後

<?php 

namespace AppBundle\Entity; 

use Doctrine\ORM\Mapping as ORM; 
use ONGR\ElasticsearchBundle\Annotation as ES; 

/** 
* Post 
* 
* @ORM\Table(name="post") 
* @ORM\Entity(repositoryClass="AppBundle\Repository\PostRepository") 
*/ 
class Post 
{ 
    /** 
    * @var int 
    * 
    * @ORM\Column(name="id", type="integer") 
    * @ORM\Id 
    * @ORM\GeneratedValue(strategy="AUTO") 
    */ 
    private $id; 

    /** 
    * @var string 
    * 
    * @ES\Property(type="string") 
    * @ORM\Column(name="title", type="string", length=255, nullable=true) 
    */ 
    private $title; 

    /** 
    * @var User 
    * 
    * @ORM\ManyToOne(targetEntity="User") 
    * @ORM\JoinColumn(name="user_id", referencedColumnName="id") 
    */ 
    private $user; 

    /** 
    * @var string 
    * 
    * @ES\Property(name="user", type="string") 
    */ 
    private $esUser; 

    /** 
    * Get id 
    * 
    * @return int 
    */ 
    public function getId() 
    { 
     return $this->id; 
    } 

    /** 
    * Set title 
    * 
    * @param string $title 
    * 
    * @return Post 
    */ 
    public function setTitle($title) 
    { 
     $this->title = $title; 

     return $this; 
    } 

    /** 
    * Get title 
    * 
    * @return string 
    */ 
    public function getTitle() 
    { 
     return $this->title; 
    } 

    /** 
    * Set user 
    * 
    * @param \AppBundle\Entity\User $user 
    * 
    * @return Post 
    */ 
    public function setUser(\AppBundle\Entity\User $user = null) 
    { 
     $this->user = $user; 

     return $this; 
    } 

    /** 
    * Get user 
    * 
    * @return \AppBundle\Entity\User 
    */ 
    public function getUser() 
    { 
     return $this->user; 
    } 

    /** 
    * @return string 
    */ 
    public function getEsUser() 
    { 
     return $this->esUser; 
    } 

    /** 
    * @param string $esUser 
    */ 
    public function setEsUser($esUser) 
    { 
     $this->esUser = $esUser; 
    } 
} 

的appbundle /文件/後

<?php 

namespace AppBundle\Document; 

use ONGR\ElasticsearchBundle\Annotation as ES; 
use AppBundle\Entity\Post as OldPost; 

/** 
* @ES\Document() 
*/ 
class Post extends OldPost 
{ 
}