讓PHP致命錯誤：require（）則試圖從服務器

Question

訪問PHP文件，我無法從Android的一側或谷歌瀏覽器訪問我的PHP文件，我也得到會在error_log文件以下錯誤：

[12-Dec-2016 13:41:53 UTC] PHP Warning: require(./Classes/Classes.php): failed to open stream: No such file or directory in /home/shaye/public_html/social/index.php on line 12 
[12-Dec-2016 13:41:53 UTC] PHP Warning: require(./Classes/Classes.php): failed to open stream: No such file or directory in /home/shaye/public_html/social/index.php on line 12 
[12-Dec-2016 13:41:53 UTC] PHP Fatal error: require(): Failed opening required './Classes/Classes.php' (include_path='.:/opt/cpanel/ea-php56/root/usr/share/pear') in /home/shaye/public_html/social/index.php on line 12 

而且也這是我的index.php文件：

 <?php ob_start(); header("charset=utf-8;"); 
$dir = str_replace("index.php","",$_SERVER['PHP_SELF']); 

$params = str_replace($dir,"",$_SERVER['REQUEST_URI']); 

$params = trim($params,"/"); 

$params = explode("/",$params); 

if(isset($params[0]) && isset($params[1])) 
{ 
require './Classes/'.basename($params[0]).".php"; 
$class = new $params[0](); 
$class->$params[1](); 
} 
else 
{ 
exit; 
} 

?> 

這是我的PHP文件在服務器中的地址：

shayea.tk/social/Classes/ 

，我使用MultipartUtility圖書館在android系統側 請幫助我不知道很多關於PHP

Answer 1

檢查以下行再次

require './Classes/'.basename($params[0]).".php"; 

我覺得路徑不匹配可能像下面或者給出正確的目錄路徑。

require '../Classes/'.basename($params[0]).".php";