PHP網站調試

Question

我有一個問題，當 無法運行此程序， 它顯示

Parse error: syntax error, unexpected 'username' (T_STRING) in C:\xampp\htdocs\fypp\index.php on line 9

<?php 
    session_start(); 
    if (isset($_POST['bttLogin'])){ 
     require 'connect.php'; 
     $username = $_POST['username']; 
     $password = $_POST['password']; 
     $result = mysquli_query($con, 'select * from account where username="'.$username.'" and password="'.$password.'") 
     if(mysqli_num_rows($result)==1) { 
      $_SESSION['username'] = $username; 
      header("Location: welcome.php"); 
     } 
     else 
      echo "account is invalid"; 
    } 
    ?> 
    <form method="post"> 
    <table cellpadding="2" cellspacing="2" border="1"> 
     <tr> 
      <td>Username</td> 
      <td><input type="text" name="username"></td> 
     </tr> 
     <tr> 
      <td>Password</td> 
      <td><input type="password"" name="password"></td> 
     </tr> 
     <tr> 
      <td>&nbsp;</td> 
      <td><input type="submit" name="bttLogin" value="Login"></td> 
     </tr> 

謝謝回答:)

Answer 1

首先，正確粘貼代碼.. 。您最後缺少</table>和</form> ...

其次，您錯過了一個簡單的撇號和一個半色調n的行

$result = mysquli_query($con, 'select * from account where username="'.$username.'" and password="'.$password.'")

此外，你應該使用mysqli_query代替mysqlui_query ...錯字！

你的代碼應該如下：

<?php 
session_start(); 
if (isset($_POST['bttLogin'])){ 
    require 'connect.php'; 
    $username = $_POST['username']; 
    $password = $_POST['password']; 
    $result = mysqli_query($con, 'select * from account where username="'.$username.'" and password="'.$password.'"'); 
    if(mysqli_num_rows($result)==1) { 
     $_SESSION['username'] = $username; 
     header("Location: welcome.php"); 
    } 
    else 
     echo "account is invalid"; 
} 
?> 

<form method="post"> 
<table cellpadding="2" cellspacing="2" border="1"> 
    <tr> 
     <td>Username</td> 
     <td><input type="text" name="username"></td> 
    </tr> 
    <tr> 
     <td>Password</td> 
     <td><input type="password"" name="password"></td> 
    </tr> 
    <tr> 
     <td>&nbsp;</td> 
     <td><input type="submit" name="bttLogin" value="Login"></td> 
    </tr> 
</table> 
</form> 

Answer 2

變化mysquli_query爲mysqli_query，因爲它不是一個有效的擴展，我認爲它的錯字錯誤。

修改的查詢：

$result = mysqli_query($con, "SELECT * FROM account 
          WHERE username='" . $username . "' 
          AND password ='". $password ."'"); 

還要注意的是，你錯過了終止分號（;）在同一行。