如何在java中編寫一個字母數字範圍檢查器,它將檢查給定的字母數字值是否在範圍內。字母數字範圍檢查器 - B3是否在B1:B10
例如: 輸入:B3,範圍:B1:B10 - 真
B1,B1:B10 - 真
B10,B1:B10 - 真
B1,B3:B10 - 假
我嘗試失敗超過1位數字,例如在B3:B10中,第二個前綴應該是'B',num應該是10,但是我得到B1和0.是否有任何錯誤的正則表達式?
public class Main {
public static final String RANGE_PATTERN = "(.+)(\\d)+:(.+)(\\d)+";
public static final String INPUT_PATTERN = "(.+)(\\d)+";
public static final Pattern P1 = Pattern.compile(RANGE_PATTERN);
public static final Pattern P2 = Pattern.compile(INPUT_PATTERN);
public static void main(String[] args) {
System.out.println(checkWithInRange("B3:B10", "B7"));
}
public static boolean checkWithInRange(String range, String input) {
Matcher m1 = P1.matcher(range);
Matcher m2 = P2.matcher(input);
if (m1.find() && m2.find()) {
String prefix1 = m1.group(1);
String num1 = m1.group(2);
String prefix2 = m1.group(3);
String num2 = m1.group(4);
String inputPrefix = m2.group(1);
String inputNum = m2.group(2);
if (prefix1.equalsIgnoreCase(prefix2) && prefix2.equalsIgnoreCase(inputPrefix)) {
int n1 = Integer.parseInt(num1);
int n2 = Integer.parseInt(num2);
int n3 = Integer.parseInt(inputNum);
if (n3 >= n1 && n3 <= n2) {
return true;
}
}
}
return false;
}
}
這段代碼有什麼問題? ''A1:B2「,」B1「'應該發生什麼? –