如何從Python日期時間對象中提取年份？

Question

我想從使用Python當前日期提取年份。

在C＃中，這看起來像：

DateTime a = DateTime.Now() 
a.Year 

什麼需要Python？

Answer 1

這其實在Python差不多了.. :-)

import datetime 
year = datetime.date.today().year 

當然，日期沒有時間關聯，所以如果你的車Ë有關過，你可以做同樣擁有完整的DateTime對象：

import datetime 
year = datetime.datetime.today().year 

（顯然沒有什麼不同，但你搶之前，你可以存儲datetime.datetime.today（）在一個變量的一年，當然）。需要注意的

一個關鍵的一點是，時間組分在某些Python版本（2.5.X樹我認爲），32位和64位的蟒蛇不同。因此，您可以在某些64位平臺上找到諸如小時/分鐘/秒之類的信息，而在32位系統上可以獲得小時/分鐘/秒。

Answer 2

import datetime 
a = datetime.datetime.today().year 

甚至（如梅里建議）

a = datetime.datetime.now().year 

甚至

a = datetime.date.today().year 

Answer 3

另外這個問題的答案似乎打即期。現在你如何解決這個問題，沒有堆棧溢出？查看IPython，這是一個具有標籤自動完成功能的交互式Python shell。

> ipython 
import Python 2.5 (r25:51908, Nov 6 2007, 16:54:01) 
Type "copyright", "credits" or "license" for more information. 

IPython 0.8.2.svn.r2750 -- An enhanced Interactive Python. 
?   -> Introduction and overview of IPython's features. 
%quickref -> Quick reference. 
help  -> Python's own help system. 
object? -> Details about 'object'. ?object also works, ?? prints more. 

In [1]: import datetime 
In [2]: now=datetime.datetime.now() 
In [3]: now. 

按Tab鍵幾次，你會用「現在」對象的成員提示：

now.__add__   now.__gt__   now.__radd__   now.__sub__   now.fromordinal  now.microsecond  now.second   now.toordinal   now.weekday 
now.__class__   now.__hash__   now.__reduce__  now.astimezone  now.fromtimestamp  now.min    now.strftime   now.tzinfo   now.year 
now.__delattr__  now.__init__   now.__reduce_ex__  now.combine   now.hour    now.minute   now.strptime   now.tzname 
now.__doc__   now.__le__   now.__repr__   now.ctime    now.isocalendar  now.month    now.time    now.utcfromtimestamp 
now.__eq__   now.__lt__   now.__rsub__   now.date    now.isoformat   now.now    now.timetuple   now.utcnow 
now.__ge__   now.__ne__   now.__setattr__  now.day    now.isoweekday  now.replace   now.timetz   now.utcoffset 
now.__getattribute__ now.__new__   now.__str__   now.dst    now.max    now.resolution  now.today    now.utctimetuple 

，你會看到now.year是其成員「現在」的對象。

Answer 4

如果你想從一個（未知）日期時間，對象的年份：

tijd = datetime.datetime(9999, 12, 31, 23, 59, 59) 

>>> tijd.timetuple() 
time.struct_time(tm_year=9999, tm_mon=12, tm_mday=31, tm_hour=23, tm_min=59, tm_sec=59, tm_wday=4, tm_yday=365, tm_isdst=-1) 
>>> tijd.timetuple().tm_year 
9999