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我需要在listview中搜索項目。我有簡單的字符串和數組適配器的數組,我把代碼放在一些不同的問題和它的工作中!但是我有一個問題,這個搜索很慢並且只有一個字母。我有一個詞「arbuz」(一個用於其他許多人),我打印一個沒有任何東西,另一個字母,然後單詞搜索「一個」,另一個 - 並且沒有這樣的詞。我希望你能夠無視我如何改善這種搜索? 我的代碼:使用edittext在列表視圖中搜索
public class FragmentWithList extends ListFragment {
ListView mainList;
EditText inputSearch;
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment_with_list, null);
mainList = (ListView) v.findViewById(android.R.id.list);
inputSearch = (EditText)v.findViewById(R.id.inputSearch);
return v;
}
public void onCreate(Bundle savedInstanceState){
setHasOptionsMenu(true);
super.onCreate(savedInstanceState);
}
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
String values[] = new String[]{"arbuz","abrikos","banan","cup","charlie","derevo","grusha","ogurets","sliva","jabloko","volk","dom","igra","pharaon","muscle"};
Comparator<String> ALPHABETICAL_ORDER1 = new Comparator<String>() {
public int compare(String object1, String object2) {
int res = String.CASE_INSENSITIVE_ORDER.compare(object1.toString(), object2.toString());
return res;
}
};
Collections.sort(Arrays.asList(values), ALPHABETICAL_ORDER1);
final ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity(),android.R.layout.simple_list_item_1,values);
mainList.setAdapter(adapter);
inputSearch.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
adapter.getFilter().filter(s.toString());
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
}
});
}
}
你可以使用自動完成的TextView,而不是使用一個EditText。自動完成Textview句柄,textwatcher,editoractionlistener本身。所以它很容易使用..試試吧。 – HourGlass