Django管理定製list_filter

Question

我沒有升級到1.3版本，此代碼不能再工作下去：

class CustomChoiceFilterSpec(ChoicesFilterSpec): 
    def __init__(self, f, request, params, model, model_admin): 
     super(CustomChoiceFilterSpec, self).__init__(f, request, params, model, model_admin) 
     self.lookup_kwarg = '%s__id__exact' % f.name # Change this to match the search of your object 
     self.lookup_val = request.GET.get(self.lookup_kwarg, None) 
     self.objects = model.objects.all() 
     self.foreign_key = f.name 
     self.foreign_key_count = {} 
     for item in model.objects.values(f.name).annotate(count=Count('pk')): 
      self.foreign_key_count[item[f.name]] = item['count'] 

    def choices(self, cl): 
     yield {'selected': self.lookup_val is None, 
       'query_string': cl.get_query_string({}, [self.lookup_kwarg]), 
       'display': ('All')} 
     items = set([getattr(i, self.foreign_key) for i in self.objects]) 
     for k in items: 
      if k is None: 
       kk = None 
      else: 
       kk = k.id 
      yield {'selected': smart_unicode(kk) == self.lookup_val, 
        'query_string': cl.get_query_string({self.lookup_kwarg: kk}), # Change .id to match what you are searching for 
        'display': '%s (%s)' % (k, self.foreign_key_count[kk])} 

FilterSpec.filter_specs.insert(0, (lambda f: getattr(f, 'compact_filter', False), CustomChoiceFilterSpec)) 

我得到的錯誤是：的init（）得到了一個意想不到的關鍵字參數「field_path」

請幫助我，

法比奧

Answer 1

找到修復的位置： -

http://djangosnippets.org/snippets/2194/