三個表查詢的MySQL

Question

我有共同affiliate_id場三個表：

impressions, clicks, commissions 

我要選擇這三個表中的所有數據，其中affiliate_id =「$ IAID」在一個查詢，然後處理數據在PHP中。

我該如何寫這樣的查詢？

Answer 1

這裏的假設您使用MYSQL的PHP​​代碼：

$qry = "SELECT im.*, cl.*, co.* 
FROM `impressions` im, `clicks` cl, `comissions` co 
WHERE im.`affiliate_id`=cl.`affiliate_id` 
AND cl.`affiliate_id`=co.`affiliate_id` 
AND im.`affiliate_id`='".$iAid."'"; 

Answer 2

SELECT <YOUR COLUMN LIST> 
    FROM impressions a, clicks b, commissions c 
WHERE a.affiliate_id = '$iAID' 
    AND a.affiliate_id = b.affiliate_id 
    AND b.affiliate_id = c.affiliate_id 

Answer 3

SELECT * FROM impressions AS i JOIN clicks AS c ON i.affiliate_id = c.affiliate_id JOIN commissions AS m ON i.affiliate_id = m.affiliate_id WHERE i.affiliate_id = '$iAid' 

應該做的伎倆

Answer 4

做左連接在MySQL查詢：

Select * from Impressions imp 
Left join clicks c on c.affiliate_id = imp.affiliate_id 
Left join commissions com on com.affiliate_id = imp_affiliate_id 
Where *** 
limit *** 
ect.... 

Answer 5

select * from 
impression a 
join clicks b on (a.affiliate_id = b.affiliate_id) 
join commissions c on (a.affiliate_id = c.affiliate_id) 
where a.affiliate_id = ? 

Answer 6

怎麼樣加入：

select * from impressions, clicks, commissions 
where impressions.affiliate_id = clicks.affiliate_id 
    and clicks.affiliate_id = commissions.affiliate_id 
    and impressions.affiliate_id = '$iAid'