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我想在python中實現一個二叉搜索樹,但我找不到刪除的解決方案。如果該項目在葉子中,那很簡單,但是如果我想要刪除的項目有兩個也有其他子項的子項,該怎麼辦?如何才能找到它的繼任者,以便我可以取代它?有沒有簡單的遞歸解決方案?二進制搜索樹Python,實現刪除
class Node:
def __init__(self, data=None, left=None, right=None):
self.data = data
self.left = left
self.right = right
class BinarySearchTree:
def __init__(self, root=None):
self.root = Node(root)
def add(self, data, node):
if node == None:
node = Node(data)
return True
if data < node.data:
if node.left == None:
node.left = Node(data)
return True
else:
self.add(data, node.left)
elif data > node.data:
if node.right == None:
node.right = Node(data)
return True
else:
self.add(data, node.right)
def preorder(self, node):
if node != None:
print(node.data)
self.preorder(node.left)
self.preorder(node.right)
def inorder(self, node):
if node != None:
self.inorder(node.left)
print(node.data)
self.inorder(node.right)
def postorder(self, node):
if node != None:
self.postorder(node.left)
self.postorder(node.right)
print(node.data)
def retreive(self,item):
node = self.root
while node != None:
if node.data == item:
break
elif item < node.data:
if node.left != None:
if node.left.data == item:
node.left = None
return True
node = node.left
else:
if node.right != None:
if node.right.data == item:
node.right= None
return True
node = node.right
if node == None:
return False
tree = BinarySearchTree()
root=Node(3)
tree.add(55,root)
tree.add(5,root)
tree.add(13,root)
tree.add(2,root)
tree.add(3,root)
tree.preorder(root)
tree.postorder(root)
tree.inorder(root)
此外,如果您對我迄今爲止撰寫的內容有任何建議,我會非常感激。提前致謝。
[Wikipedia article](http://en.wikipedia.org/wiki/Binary_search_tree#Deletion)對這裏使用的方法有很好的解釋。 –