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我有一個表信息作爲圖像下方如何從PHP返回值到java?
的ID設置爲自動遞增。當addInformation被調用時,它會將數據插入到信息中。
addInformation(name, weather, date2, status, first1[1], last1[1]);
AddInformation功能
public void addInformation(final String name, final String weather, final String date2, final String status, final String timeIn, final String timeOut) {
class AddInfo extends AsyncTask<String, Void, String> {
ProgressDialog loading;
@Override
protected void onPreExecute() {
super.onPreExecute();
loading = ProgressDialog.show(WorkDetailsTable.this, "Please Wait", null, true, true);
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
loading.dismiss();
Toast.makeText(getApplicationContext(),s, Toast.LENGTH_LONG).show();
//addWorkForce(Sub, NoP, NoH, Long.parseLong(s));
// addWorkDetails(results, Long.parseLong(s));
}
@Override
protected String doInBackground(String... params) {
HashMap<String, String> data = new HashMap<String, String>();
data.put(Config.KEY_USER_NAME, name);
data.put(Config.KEY_WEATHER, weather);
data.put(Config.KEY_DATE, date2);
data.put(Config.KEY_STATUS, status);
data.put(Config.KEY_TIMEIN, timeIn);
data.put(Config.KEY_TIMEOUT, timeOut);
RequestHandler rh = new RequestHandler();
String result = rh.sendPostRequest(Config.ADD_INFORMATION, data);
String response=? // get last Id from php
return result;
}
}
AddInfo ru = new AddInfo();
ru.execute(name, weather, date2, status, timeIn, timeOut);
}
我在PHP新的,現在想從表中信息獲取lastID和返回值到Android。但我得到未定義的索引。
<?php
class AddInformation{
function response(){
/** @var mysqli $con */
require_once('dbConnect.php'); //$con = new mysqli('127.0.0.1', 'root', '', 'so');
$name = $con->real_escape_string($_POST['name']);
$weather = $con->real_escape_string($_POST['weather']);
$date = $con->real_escape_string($_POST['date']);
$status = $con->real_escape_string($_POST['status']);
$timein = $con->real_escape_string($_POST['timeIn']);
$timeout = $con->real_escape_string($_POST['timeOut']);
$con->query("INSERT INTO information (name, weather, date, status, time_in, time_out) VALUES ('$name', '$weather', '$date', $status', '$timeIn', '$timeOut')");
echo $con->insert_id;
}
}
$ai = new AddInformation();
$ai->response();
?>
- 如何最後的ID從PHP(插入LastId)返回響應(JAVA)/
- 如何在PHP解決不確定的指數?
有人可以幫我嗎?讚賞。
你應該使用MySQLi的[準備語句](http://php.net/manual/en/mysqli.quickstart.prepared-statements.php)來查看你正在使用的MySQLi。 – Script47
@ Script47它可以返回值爲java? –