無法輸出保存到Excel工作簿時，Python中填充數據

Question

當我運行下面的代碼一切正常發現：

wb7 = load_workbook('define2.xlsx') 
ws = wb7.worksheets[0] 
ws.cell(row=3,column=2).value = "hey" 
wb7.save('define2.xlsx') 

但是，當我把最後一行代碼在不同的代碼結束時，我得到一個錯誤信息。而且是正確生成該錯誤，因爲我跨過線：

wb7.save('define2.xlsx') 

我得到的錯誤信息是

TypeError: %d format: a number is required, not tuple 

我覺得奇怪，因爲我看不出爲什麼wb7必須是一個數。所有我想要做的是輸出一些數據到Excel然後保存Excel工作簿。我做了很多次，沒有任何問題。一定是這樣，wb7變量得到了改變，但顯然沒有改變。在調試器中，運行代碼後沒有發現wb7被更改的證據。我也得到我的控制檯如下：

/Library/Python/2.7/site-packages/openpyxl/reader/worksheet.py:322: UserWarning: Unknown extension is not supported and will be removed 
    warn(msg) 
Traceback (most recent call last): 

    File "/Applications/PyCharm CE.app/Contents/helpers/pydev/pydevd.py", line 2357, in <module> 
    globals = debugger.run(setup['file'], None, None, is_module) 

    File "/Applications/PyCharm CE.app/Contents/helpers/pydev/pydevd.py", line 1777, in run 
    pydev_imports.execfile(file, globals, locals) # execute the script 

    File "/Users/kylefoley/PycharmProjects/untitled3/temp5.py", line 1682, in <module> 
    wb7.save('define2.xlsx') 

    File "/Library/Python/2.7/site-packages/openpyxl/workbook/workbook.py", line 263, in save 
    save_workbook(self, filename) 

    File "/Library/Python/2.7/site-packages/openpyxl/writer/excel.py", line 239, in save_workbook 
    writer.save(filename, as_template=as_template) 

    File "/Library/Python/2.7/site-packages/openpyxl/writer/excel.py", line 222, in save 
    self.write_data(archive, as_template=as_template) 

    File "/Library/Python/2.7/site-packages/openpyxl/writer/excel.py", line 80, in write_data 
    self._write_worksheets(archive) 

    File "/Library/Python/2.7/site-packages/openpyxl/writer/excel.py", line 163, in _write_worksheets 
    xml = sheet._write(self.workbook.shared_strings) 

    File "/Library/Python/2.7/site-packages/openpyxl/worksheet/worksheet.py", line 778, in _write 
    return write_worksheet(self, shared_strings) 

    File "/Library/Python/2.7/site-packages/openpyxl/writer/worksheet.py", line 198, in write_worksheet 
    dim = Element('dimension', {'ref': '%s' % worksheet.calculate_dimension()}) 

    File "/Library/Python/2.7/site-packages/openpyxl/worksheet/worksheet.py", line 420, in calculate_dimension 
    get_column_letter(max_col), max_row 

下面是完整的代碼：

wb7 = load_workbook('define2.xlsx') 
ws = wb7.worksheets[0] 
temp_list = [] 
category = ['r','s','t'] 
relat = [] 
srelat = [] 
trelat = [] 
word_type = [] 
atomic_relations = [] 
list1 = [] 
list4 = [] 
det = [] 
adj = [] 
adv = [] 
noun = [] 
cor = [] 
lcon = [] 
subo = [] 
synon = [] 
redundant = [] 
aux = [] 
atomic_relata = [] 
negg = [] 
dnoun = [] 
det_pairs = [] 
definitions = [] 
syn_pairs = [] 
relations = [] 
relations2 = [] 
ind_words = [] 
ind_num = [] 
particles = [] 
osent = [] 
sn = 1 

i = 0 
for row in ws.rows: 
    i += 1 
    if i == 430: 
     pp = 5 
    str1 = row[0].value 
    str5 = copy.copy(str1) 
    str2 = row[1].value 
    if str1 != None and str2 != None: 

     str3 = row[2].value 
     defin = row[3].value 
     if str2 != None: 
      str2 = str2.strip() 
     if str3 != None: 
      str3 = str3.strip() 
     atom = copy.copy(str1) 
     str5 = str1[0:1] 
     atom = atom[1:2] 
     str8 = copy.copy(str1) 
     str8 = str1[3:] 
     if str5 in category: 
      word_type.append([str3,str5]) 
     elif str5 != 'z': 
      word_type.append([str2, str5]) 

     if str5 in category: 
      if str5 == 'r': 
       relat.append(str3) 
      elif str5 == 's': 
       srelat.append(str3) 
      elif str5 == 't': 
       trelat.append(str3) 
      if atom == 'a': 
       atomic_relations.append(str3) 
       atom = 'b' 
      list2a = [str2,str3] 
      relations.append(list2a) 
      relations2.append(str2) 
     elif str5 == 'a': 
      adj.append(str2) 
     elif str5 == 'b': 
      aux.append(str2) 
     elif str5 == 'c': 
      cor.append(str2) 
     elif str5 == 'd': 
      det.append(str2) 
     elif str5 == 'e': 
      adv.append(str2) 
     elif str5 == 'l': 
      lcon.append(str2) 
     elif str5 == 'm': 
      negg.append(str3) 
     elif str5 == 'n': 
      noun.append(str2) 
     elif str5 == 'u': 
      subo.append(str2) 
     if atom == 'n': 
      dnoun.append(str2) 
     elif atom == 'a': 
      atomic_relata.append(str2) 
     elif atom == 'q': 
      particles.append(str2) 
     elif atom == 'r': 
      redundant.append(str2) 
     if atom == 'p' or atom == 'd': 
      if atom == 'p': 
       atom = 7 
      elif atom == 'd': 
       atom = 5 
      list1a = [str2, atom] 
      ind_words.append(str2) 
      ind_num.append(list1a) 
     elif atom == 's': 
      str6 = defin[defin.find("=")+1:-1] 
      str6 = str6.strip() 
      str7 = defin[1:defin.find("=")] 
      str7 = str7.strip() 
      list3a = [str7, str6, defin] 
      syn_pairs.append(list3a) 
      synon.append(str7) 
     elif atom == 'n': 
      str6 = defin[defin.find(".")+1:] 
      str7 = defin[:defin.find(".")] 
      det_pairs.append([str7, str6, str2]) 
     if atom != 'a': 
      if str5 in category: 
       definitions.append([str3, defin]) 
      else: 
       definitions.append([str2, defin]) 

words = [adj, cor, det, adv, lcon, noun, relat, srelat, trelat, subo, aux, negg, dnoun] 
word_type.sort() 
syn_pairs.sort() 

del word_type[0] 
test_sent = [] 

j = 0 
for i in ws.rows: 
    j += 1 
    if j > 263: 
     break 
    if j == 169: 
     pp = 7 
    str1 = i[0].value 
    str2 = i[1].value 
    if str1 != None: 
     str2 = str2.strip() 
     if str1[1:2] == 's' and j>139: 
      str3 = findinlist(str2,syn_pairs,0,1) 
      if str3 == None: 
       pp = 7 
      str4 = findinlist(str3, word_type,0,1) 
      if str4 == None: 
       pp = 7 
      ws.cell(row=i,column=1).value = str4 + 'sx' 


wb7.save('define2.xlsx') 

Answer 1

問題解決了：不是

ws.cell(row=i,column=1).value = str4 + 'sx' 

我應該寫：

ws.cell(row=j,column=1).value = str4 + 'sx' 

t右側的值他=符號必須是一個數字，而我是一排不是數字。