從JSON中刪除ID，然後將其添加到每組數據中。

我一直在運行一個Python腳本，它刪除每組數據的ID，以允許它上傳到BigQuery。現在，我不想刪除這些信息，而是想將其插入每組數據中，以便稍後參考。從JSON中刪除ID，然後將其添加到每組數據中。

這就是我一直在接收JSON，並將其上傳到BigQuery中的代碼。

{"AppName": "DataWorks", "foundedPeripheralCount": 1, "version": "1.6.1(8056)", "deviceType": "iPhone 6", "createdAt": "2017-04-05T07:05:30.408Z", "updatedAt": "2017-04-05T07:08:49.569Z", "connectedPeripheralCount": 1, "iOSVersion": "10.2.1"}

firebase = firebase.FirebaseApplication('https://dataworks-356fa.firebaseio.com/') 
result = firebase.get('/PeripheralCount', None) 
id_keys = map(str, result.keys()) #filter out ID names 


with open("firetobq_peripheral2.json", "w") as outfile: 
    for id in id_keys: 
    json.dump(result[id], outfile, indent=None) 
    outfile.write("\n")

這是JSON的方式，而不與代碼一起任何編輯創建。

{"1972FDEE-E2C0-4E8C-BD00-630315D4AEDE": {"AppName": "DataWorks", "foundedPeripheralCount": 1, "version": "1.6.1(8056)", "deviceType": "iPhone 6", "connectedPeripheralCount": 1, "updatedAt": "2017-04-05T07:08:49.569Z", "Peripherals": {"1CA726ED-32B1-43B4-9071-B58BBACE20A8": "Arduino"}, "createdAt": "2017-04-05T07:05:30.408Z", "iOSVersion": "10.2.1"}

其中1972FDEE-E2C0-4E8C-BD00-630315D4AEDE是ID。

firebase = firebase.FirebaseApplication('https://dataworks-356fa.firebaseio.com/') 
result = firebase.get('/PeripheralCount', None) 
id_keys = map(str, result.keys()) #filter out ID names 


with open("firetobq_peripheralx.json", "w") as outfile: 
    # for id in id_keys: 
    json.dump(result, outfile, indent=None) 
    outfile.write("\n")

我希望它看起來像這樣。

{"ID": "1972FDEE-E2C0-4E8C-BD00-630315D4AEDE", "AppName": "DataWorks", "foundedPeripheralCount": 1, "version": "1.6.1(8056)", "deviceType": "iPhone 6", "connectedPeripheralCount": 1, "updatedAt": "2017-04-05T07:08:49.569Z", "Peripherals": {"1CA726ED-32B1-43B4-9071-B58BBACE20A8": "Arduino"}, "createdAt": "2017-04-05T07:05:30.408Z", "iOSVersion": "10.2.1"}

感謝您的幫助！

來源

2017-07-27 W. Stephens

首先定義一個基dict保存您的ID：

out = { 
    "ID": "1972FDEE-E2C0-4E8C-BD00-630315D4AEDE", 
}

然後，更新out與原點JSON：

out.update(js_dict.get(out.get('ID')))

js_dict是你上面提到的JSON。

來源

2017-07-27 03:32:48 LuCima

從JSON中刪除ID，然後將其添加到每組數據中。

回答

相關問題