我有一個關於react-redux的問題,我正在玩一些小的測試代碼,以瞭解它是如何工作的。react-redux connect不重新渲染組件,但道具得到更新
Git repository with problematic code
一切看起來正確,動作生成器,減速機,調度員,mapStateToProps和連接功能。
我也會在這裏粘貼代碼:
沒有狀態變異。
但是,當子藤傳遞給它從主(問題的組件)TodoBox(index.jsx)(index.jsx)調用函數(onClick事件),然後 1.調度員被炒魷魚 2.減速,都會激發和回報與預期的更新 3. mapStateToProps新的國家,都會激發和收益預期的結果
但TodoBox組件,請不要重新渲染 從瀏覽器控制檯,我可以看到this.props的TodoBox已更新的值。
這是怎麼回事,我不明白,檢查了很多文章和例子,但沒有匹配。
誰能檢測到問題,我需要幫助。
app.js(反應入口點)
import React from 'react';
import ReactDOM from 'react-dom';
import TodoBox from './views/index.jsx';
import { createStore } from 'redux';
import { Provider } from 'react-redux';
import * as actions from './redux_actions.js';
var data = JSON.parse(document.getElementById('initial-data').getAttribute('data-json'));
const todosReducer = function (state={todos: data}, action) {
switch(action.type) {
case actions.UPDATE_TODO:
let newState = Object.assign({}, state)
let upd1 = updateRow(newState.todos, 'titel', action.todoUpdate.id, 'checked', action.todoUpdate.checked)
newState.todos = updateRow(upd1, 'titel', action.todoUpdate.id, 'detail', action.todoUpdate.checked ? 'Done' : 'Sorry not done')
return newState
break;
default:
return state;
}
}
function updateRow(tab, where, val, updfield, val2) {
tab.forEach((row) => {
row[where] === val ? row[updfield] = val2 : null
})
return tab
}
var Store = createStore(todosReducer)
ReactDOM.render(<Provider store={Store}><TodoBox /></Provider>, document.getElementById("app"));
index.jsx
import React from 'react';
import * as Redux from 'redux';
import { connect } from 'react-redux'
import * as actions from '../redux_actions.js'
class TodoBox extends React.Component {
render() {
return (
<div className="todoBox">
<h1>Todos</h1>
<TodoList data={this.props.todos} func={this.props.handleChange}/>
<TodoForm />
</div>
);
}
}
class TodoList extends React.Component {
render() {
let todo = this.props.data.map((todos) => { return <Todo titel={todos.titel} func={this.props.func} check={todos.checked} key={todos.titel}>{todos.detail}</Todo> })
return (
<div className="todoList">
<table style={{border: "2px solid black"}}>
<tbody>
{todo}
</tbody>
</table>
</div>
);
}
}
class Todo extends React.Component {
render() {
return (
<tr>
<td style={style.tableContent}>
<input id={this.props.titel} type="checkbox" checked={this.props.checked} onChange={this.props.func}/>
</td>
<td style={style.tableContent}>{this.props.titel}</td>
<td style={style.tableContent}>{this.props.children}</td>
</tr>
);
}
}
Todo.propTypes = {
titel: React.PropTypes.string.isRequired
}
class TodoForm extends React.Component {
render() {
return (
<div className="todoForm">
I am a TodoForm.
</div>
);
}
}
let style = {
tableContent: {
border: "1px solid black"
}
};
const mapStateToProps = function (state) {
return { todos: state.todos }
}
const mapDispatchToProps = function(dispatch) {
return {
handleChange: function(event) {
dispatch(actions.actionUpdateTodo({id: event.target.id, checked: event.target.checked}));
}
}
}
export default connect(mapStateToProps, mapDispatchToProps)(TodoBox)
redux_actions.jsx
export const UPDATE_TODO = 'UPDATE_TODO'
export function actionUpdateTodo(todoUpdate) {
return { type: UPDATE_TODO, todoUpdate: todoUpdate }
}
謝謝你的回答!我認爲'讓newState = Object.assign({},state)'創建全部新對象和所有內容。其實我不明白它爲什麼會發生變異。使用擴展運算符它沒有工作,但下一個建設工作'newState.todos = Object.assign([],updateRow(upd1,'titel',action.todoUpdate.id,'detail',action.todoUpdate.checked?'Done ':'對不起'))' – sigvamo