列表分配索引超出範圍錯誤

Question

我想創建一個簡單的數組程序並打印出數組元素，但在我輸入員工2的值後說：IndexError：list assignment index out of range。

#Create constant for the number of employees. 
SIZE = 3 

#Create an array to hol the number of hours worked by each employee. 
hours = [SIZE] 

#Get the hours worked by employee 1. 
hours[0] = int(input("Enter the hours worked by employee 1: ")) 

#Get the hours worked by employee 2. 
hours[1] = int(input("Enter the hours worked by employee 2: ")) 

#Get the hours worked by employee 3. 
hours[2] = int(input("Enter the hours worked by employee 3: ")) 

#Display the values entered. 
print("The hours you entered are:") 
print(hours[0]) 
print(hours[1]) 
print(hours[2]) 

Answer 1

值Python沒有字面數組：它有名單。 hours = [SIZE]不會創建包含3個元素的列表：它會創建一個包含1個元素的列表。您應該使用append()將項目添加到列表中，而不是索引超過數組末尾。

正確的代碼看起來像這樣的元素添加到列表：

hours.append(int(input("Enter the hours worked by employee 1: "))) 
hours.append(int(input("Enter the hours worked by employee 2: "))) 
hours.append(int(input("Enter the hours worked by employee 3: "))) 

從評論，似乎你正在學習從僞教科書代碼：這是美妙的。請記住，雖然某些常用於僞代碼的慣例，或者有時類似於C語言的慣例在其他編程語言中可能會有所不同。例如，在C中，這聲明瞭一個名爲x的50個字符的數組。

char x[50]; 

在Python中，不能使用相同的語法。祝你好運。

Answer 2

您似乎對如何在Python中使用數組工作有錯誤的想法。本質上講，當你鍵入

#Create constant for the number of employees. 
SIZE = 3 

#Create an array to hol the number of hours worked by each employee. 
hours = [SIZE] 

你在做什麼是創建一個元素的數組的3

hours = [3]