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我有xml，看起來有點類似於以下內容。我需要從屬性和標籤獲取值並存儲它們。但我不明白如何到達2級（3,4等）嵌套元素。我使用以下代碼，我發現在互聯網上，它使用DOM但我不能得到正確的RegNumber及其屬性。提前致謝。Java：閱讀許多嵌套元素的XML
nodeList = xmldocument.getElementsByTagName("Header"); if (nodeList != null && nodeList.getLength() > 0) { for (int i = 0; i < nodeList.getLength(); i++) { //get the header element Element header = (Element) nodeList.item(i); System.out.println("Element: " + ((Element)nodeList.item(i)).getNodeName()); System.out.println(header.getAttribute("time")); } } nodeList = xmldocument.getElementsByTagName("Document"); if (nodeList != null && nodeList.getLength() > 0) { for (int i = 0; i < nodeList.getLength(); i++) { //get the document element Element document = (Element) nodeList.item(i); System.out.println("Element: " + ((Element)nodeList.item(i)).getNodeName()); System.out.println(document.getAttribute("Id")); nodeList = document.getElementsByTagName("RegNumber"); for (int j = 0; j < nodeList.getLength(); j++) { //get the RegNumber element Element regNumber = (Element) nodeList.item(j); System.out.println("Element: " + ((Element)nodeList.item(j)).getNodeName()); System.out.println(regNumber.getAttribute("regpoint")); } } }
XML：
<XML xsi:schemaLocation="http://www.codetools.it XSD2.xsd" xmlns="http://www.codetools.it" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Header time="2001-12-17T09:30:47Z" />
<Document Id="456">
<RegNumber regpoint="" regdate="2001-12-17T09:30:47Z">123/456</RegNumber>
<Confident flag="0"/>
<DocNumber kind="">
<RegNumber RegPoint="" regdate="2001-12-17T09:30:47Z">456/789</RegNumber>
<Organization fullname="lol" shortname="" ownership="lol" ogrn="78945612" inn="">
<OfficialPerson>
<Name Firstname="John"/>
<Official Department="" post=""/>
<SignDate>2001-12-17T09:30:47Z</SignDate>
</OfficialPerson>
<Econtact type="1">[email protected]</Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
</Organization>
</DocNumber>
<DocTransfer os="Windows" type=".docx" type_ver="" char_set="" description="kkkk">
</DocTransfer>
<Reghistory idnumber="">
<RegNumber RegPoint="" regdate=""/>
<Organization fullname="" shortname="" ownership="" ogrn="" inn="">
<Econtact type=""/>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
</Organization>
</Reghistory>
<Author>
<Organization fullname="" shortname="" ownership="" ogrn="12345678" inn="">
<OfficialPerson>
<Name Firstname="" />
<Official Department="" post=""/>
<SignDate>2011-12-17T09:30:47Z</SignDate>
</OfficialPerson>
<Econtact type="Рї">[email protected]</Econtact>
<Address street="" postcode="1234" postbox="" flat="" district="" region="" country="" nontypical="" house="12"/>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""/>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
<SignDate/>
<Rank privilege="" socialposition="" sex=""/>
</PrivatePerson>
</Author>
<Validator attestation="0">
<DocNumber kind="наказ">
<RegNumber RegPoint="" regdate="2001-12-17T09:30:47Z"/>
<Organization fullname="" shortname="" ownership="" ogrn="14725836" inn="">
<Econtact type="Рї">[email protected]</Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
</Organization>
</DocNumber>
<Organization fullname="" shortname="РљРњРЈ" ownership="" ogrn="96325878" inn="">
<Econtact type="String">[email protected]</Econtact>
<Address street="Пушкіна" settlement="" postcode="4563" postbox="" flat="" district="" region="" country="" nontypical="" house="23"/>
<OfficialPerson>
<Name Surname="" Firstname="" Fathername=""/>
<Official Department="" post=""/>
<SignDate>2011-12-17T09:30:47Z</SignDate>
</OfficialPerson>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
<SignDate></SignDate>
<Rank privilege="" socialposition="" sex=""/>
</PrivatePerson>
</Validator>
<Addressee>
<Referred id="" retype="">
<RegNumber regdate="" regpoint=""/>
<TaskNumber taskDate=""/>
</Referred>
<Organization fullname="String" shortname="" ownership="" ogrn="85236974" inn="">
<OfficialPerson>
<Name Surname="" Firstname="" Fathername=""/>
<Official Department="" post=""/>
</OfficialPerson>
<Econtact type="Рї">[email protected]</Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" type="" house=""/>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
<Address street="" settlement="" postcode="" postbox="" flat="" district="" region="" country="" nontypical="" house=""/>
<Rank privilege="" socialposition="" sex=""/>
</PrivatePerson>
</Addressee>
<Writer>
<Organization fullname="" shortname="" ownership="" ogrn="" inn="">
<OfficialPerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
</OfficialPerson>
</Organization>
<PrivatePerson>
<Name Surname="" Firstname="" Fathername=""/>
<Econtact type=""></Econtact>
</PrivatePerson>
</Writer>
</Document>
編輯。據建議，我試圖弄清楚JAXB thingy。 xjc工具生成了3個類：ObjectFactory，package-info，XML。我發現這個代碼從XML創建對象：
public static void main(String[] args) {
try {
File file = new File("F:\\Untitled3.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(XML.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
XML xml = (XML) jaxbUnmarshaller.unmarshal(file);
System.out.println(xml);
} catch (JAXBException e) {
e.printStackTrace();
}
}
這是正確的方法，或者我需要使用的ObjectFactory？：
ObjectFactory f =new ObjectFactory();
XML xml1 = f.createXML();
如何創建對象所有的標籤和屬性，然後從它創建xml文件？我新來java和jaxb的東西，所以請忍受我。
你真的想手動解析XML嗎？有更好的方法，看看[JAXB]（http://en.wikipedia.org/wiki/Java_Architecture_for_XML_Binding） –
謝謝你的回答。我真的不知道我應該用什麼。我剛剛通過Google搜索「Java xml read」發現了Dom的東西，它對我來說很簡單。您能否給我一些關於JAXB初學者的鏈接？ – bunnyjesse112