2013-03-31 55 views
0

我只是學習如何使用谷歌地圖從我的數據庫信息,我有一些麻煩。我可以讓地圖出現,沒有問題,並且我的數據庫中的信息在php頁面中被正確拉取,但我似乎無法在我的html頁面中調用該信息。我試圖讓小圖標出現在數據庫中每個位置的地圖上,但到目前爲止,沒有任何內容出現在Google地圖框之外。任何幫助將不勝感激!與谷歌地圖使用PHP

googleMap.php

<? 
$username="myUsername"; 
$password="myPassword"; 
$database="myDatabase"; 
?> 

<?php 

function parseToXML($htmlStr) 
{ 
$xmlStr=str_replace('<','&lt;',$htmlStr); 
$xmlStr=str_replace('>','&gt;',$xmlStr); 
$xmlStr=str_replace('"','&quot;',$xmlStr); 
$xmlStr=str_replace("'",'&#39;',$xmlStr); 
$xmlStr=str_replace("&",'&amp;',$xmlStr); 
return $xmlStr; 
} 

// Opens a connection to a MySQL server 
$connection=mysql_connect (localhost, $username, $password); 
if (!$connection) { 
die('Not connected : ' . mysql_error()); 
} 

// Set the active MySQL database 
$db_selected = mysql_select_db($database, $connection); 
if (!$db_selected) { 
die ('Can\'t use db : ' . mysql_error()); 
} 

// Select all the rows in the markers table 
$query = "SELECT * FROM markers"; 
$result = mysql_query($query); 
if (!$result) { 
die('Invalid query: ' . mysql_error()); 
} 

// Start XML file, echo parent node 


// Iterate through the rows, printing XML nodes for each 
while ($row = @mysql_fetch_assoc($result)){ 
// ADD TO XML DOCUMENT NODE 
echo 'marker '; 
echo 'name="' . parseToXML($row['name']) . '" '; 
echo 'address="' . parseToXML($row['address']) . '" '; 
echo 'lat="' . $row['lat'] . '" '; 
echo 'lng="' . $row['lng'] . '" '; 
echo 'type="' . $row['type'] . '" '; 
echo '/>'; 
} 
?> 

googleMap.html

<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="content-type" content="text/html; charset=utf-8"/> 
<title>Google Maps AJAX + mySQL/PHP Example</title> 
<script src="http://maps.google.com/maps/api/js?sensor=false" 
     type="text/javascript"></script> 
<script type="text/javascript"> 
//<![CDATA[ 

var customIcons = { 
    restaurant: { 
    icon: 'http://labs.google.com/ridefinder/images/mm_20_blue.png', 
    shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png' 
    }, 
    bar: { 
    icon: 'http://labs.google.com/ridefinder/images/mm_20_red.png', 
    shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png' 
    } 
}; 

function load() { 
    var map = new google.maps.Map(document.getElementById("map"), { 
    center: new google.maps.LatLng(47.6145, -122.3418), 
    zoom: 13, 
    mapTypeId: 'roadmap' 
    }); 
    var infoWindow = new google.maps.InfoWindow; 

    downloadUrl(googleMap.php, function(data) { 
    var xml = data.responseXML; 
    var markers = xml.documentElement.getElementsByTagName("marker"); 
    for (var i = 0; i < markers.length; i++) { 
     var name = markers[i].getAttribute("name"); 
     var address = markers[i].getAttribute("address"); 
     var type = markers[i].getAttribute("type"); 
     var point = new google.maps.LatLng(
      parseFloat(markers[i].getAttribute("lat")), 
      parseFloat(markers[i].getAttribute("lng"))); 
     var html = "<b>" + name + "</b> <br/>" + address; 
     var icon = customIcons[type] || {}; 
     var marker = new google.maps.Marker({ 
     map: map, 
     position: point, 
     icon: icon.icon, 
     shadow: icon.shadow 
     }); 
     bindInfoWindow(marker, map, infoWindow, html); 
    } 
    }); 
} 

function bindInfoWindow(marker, map, infoWindow, html) { 
    google.maps.event.addListener(marker, 'click', function() { 
    infoWindow.setContent(html); 
    infoWindow.open(map, marker); 
    }); 
} 

function downloadUrl(url, callback) { 
    var request = window.ActiveXObject ? 
     new ActiveXObject('Microsoft.XMLHTTP') : 
     new XMLHttpRequest; 

    request.onreadystatechange = function() { 
    if (request.readyState == 4) { 
     request.onreadystatechange = doNothing; 
     callback(request, request.status); 
    } 
    }; 

    request.open('GET', url, true); 
    request.send(null); 
} 

function doNothing() {} 
</script> 
</head> 

<body onload="load()"> 
<div id="map" style="width: 500px; height: 300px"></div> 
/body> 
</html> 
+0

你有搗鼓的人一起玩? – qooplmao

回答

0

在你的PHP文件你呼應的每一行。但標記不正確。它應該是一個適當的XML節點,你只顯示一些文本。

header("Content-type: text/xml"); 

// Start XML file, create parent node 
$doc = domxml_new_doc("1.0"); 
$node = $doc->create_element("markers"); 
$parnode = $doc->append_child($node); 

// Iterate through the rows, adding XML nodes for each 
while ($row = @mysql_fetch_assoc($result)){ 
    // ADD TO XML DOCUMENT NODE 
    $node = $doc->create_element("marker"); 
    $newnode = $parnode->append_child($node); 

    $newnode->set_attribute("name", $row['name']); 
    $newnode->set_attribute("address", $row['address']); 
    $newnode->set_attribute("lat", $row['lat']); 
    $newnode->set_attribute("lng", $row['lng']); 
    $newnode->set_attribute("type", $row['type']); 
} 

請參閱此鏈接:https://developers.google.com/maps/articles/phpsqlajax_v3#outputxml

+0

添加您建議的「<」不會影響地圖的顯示。另外,在我添加它之前,當我在瀏覽器中打開它時,php頁面正確列出了所有信息(名稱,地址,緯度等...),但添加「<」後,php頁面上沒有任何內容我在瀏覽器中查看它 – user2228503

+0

oh nvm你完全改變了你的答案haha – user2228503

+0

是的,但延伸是相同的。事實上你沒有在瀏覽器中看到任何內容,並添加<很好! XML是一種數據標記語言;所以它不會顯示一些東西。請閱讀我在_new_答案中提供的鏈接!該教程非常棒! – stUrb