MySQL定製組concat

我需要轉換我的查詢結果，因此多行具有相同的外鍵只是一行。我可以做到這一點與分組。問題是在我的一個列中，我想用不同的分組連接一些列。例如我的表包含somting這樣的：MySQL定製組concat

shopId  Brand Category Color  QTY 
---------------------------------------------- 
15   Dell  NoteBook Red  5 
15   Dell  NoteBook Blue  1 
15   HP  NoteBook red  2 
15   HP  NetBook  red  3 
14   Sony  NoteBook yellow 1 
14   Acer  Tablet  red  10

品牌，類別和顏色都從他們的外鍵檢索。我想現在這個結果像

ShopId  Dell Color    HP Color etc... 
----------------------------------------------------------- 
15   6  red:5, Blue:1  2  red:2  
14 ..............

我的查詢

我通過shopId和使用金額和案例statment是一個很容易找到工作的每個品牌和類別的總數量劃分它們。我的問題是我如何連接店鋪，類別，品牌分組的顏色和數量（總分組由shopId不是商店，類別，品牌）？

我tabale是

 
CREATE TABLE `shopstorage` (
`color` int(11) NOT NULL, 
`category` int(11) NOT NULL, 
`brand` int(11) NOT NULL, 
`shop` int(11) NOT NULL, 
`date` date NOT NULL, 
`qty` tinyint(4) NOT NULL, 
PRIMARY KEY (`color`,`category`,`brand`,`shop`,`date`), 
KEY `clrEpClr` (`color`), 
KEY `clrEpCat` (`category`), 
KEY `clrEpshop` (`shop`), 
KEY `clrEpBrand` (`brand`), 
CONSTRAINT `SSBrand` FOREIGN KEY (`brand`) REFERENCES `brand` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION, 
CONSTRAINT `SSCat` FOREIGN KEY (`category`) REFERENCES `productcategory` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION, 
CONSTRAINT `SSClr` FOREIGN KEY (`color`) REFERENCES `color` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION, 
CONSTRAINT `SSShop` FOREIGN KEY (`shop`) REFERENCES `shop` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION 
) ENGINE=InnoDB DEFAULT CHARSET=utf8

和我的不完備查詢

 
select 
    shop.name, shop.floor, shop.no, 
    sum(case when brand.name ='ASUS' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as ASUS, 
    sum(case when brand.name ='HP' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as HP, 
    sum(case when brand.name ='Sony' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as Sony, 
    sum(case when brand.name ='Dell' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as Dell, 
    sum(case when brand.name ='ASUS' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as ASUS, 
    sum(case when brand.name ='HP' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as HP, 
    sum(case when brand.name ='Sony' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as Sony, 
    sum(case when brand.name ='Dell' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as Dell, 
    sum(case when brand.name ='ASUS' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as ASUS, 
    sum(case when brand.name ='HP' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as HP, 
    sum(case when brand.name ='Sony' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as Sony, 
    sum(case when brand.name ='Dell' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as Dell 
from shopstorage 
    join brand on shopstorage.brand=brand.id 
    join color on shopstorage.color=color.id 
    join productcategory on shopstorage.category=productcategory.id 
    join shop on shop.id = shopstorage.shop 
group by shopstorage.shop

我正在尋找一種方式，每個總和後添加一列用於指定每種顏色的數量，例如，如果惠普是15它有7個紅色和8個藍色筆記本。我嘗試了GROUP_Concat，但由於分組錯誤，它沒有顯示正確的結果。

來源

2012-08-13 Soheil

你想要一個「樞軸」。搜索那個術語 – Bohemian 2012-08-13 11:42:12

我已經在搜索那個。但坦克:) – Soheil 2012-08-13 12:05:43

向我們展示您的表結構（SHOW CREATE TABLE your_table'的結果）和您的查詢到目前爲止。 – Jocelyn 2012-08-13 13:39:13

我找出答案並希望與他人分享。我添加了下面的代碼在我的查詢中的每個總和後

,group_concat(case when brand.name='{$brand['name']}' and category={$category['id']} then concat(color.name,':',num) end) as {$brand['name']}C

{$品牌[「名稱」]}和{$類別[「ID」]}是在我的PHP代碼變量品牌和類別之間迭代我不知道爲什麼花了這麼長時間找到這樣一個簡單的解決方案：P羞辱我：D

來源

2012-08-14 07:42:17 Soheil

MySQL定製組concat

回答

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