希望我只是傳遞一些愚蠢的東西。EditText getText返回空
問題:我的EditText(2)getText()返回空字符串「」@ runtime in the LISTENER。請參閱onClick(...)
我懷疑它必須與我如何在構建器上create()後對對話框中的searchDialog和setContentView充氣,但無法弄清楚。
CODE:
private void initSearch() {
results = new ArrayList<Photo>();
AlertDialog.Builder searchDialog = new AlertDialog.Builder(this);
AlertDialog dialog = searchDialog.create();
LayoutInflater inflater = this.getLayoutInflater();
dialog.setContentView(R.layout.search_dialog);
searchDialog.setView(inflater.inflate(R.layout.search_dialog, null));
final EditText tagField = (EditText) dialog.findViewById(R.id.tagField);
final EditText valueField = (EditText) dialog.findViewById(R.id.valueField);
searchDialog.setTitle("Search Photos");
searchDialog.setMessage("Specify tag and value...");
searchDialog.setPositiveButton("Search", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
try { // PROBLEM: first two lines
String tag = tagField.getText().toString(); // TAG WILL BE EMPTY
String value = valueField.getText().toString(); // VALUE WILL BE EMPTY
String criteria = tag+":\""+value+"\"";
ArrayList<String> tags = new ArrayList<String>();
tags.add(criteria);
HomeScreen.results = c.getPhotosByTag(tags);
if(!tag.equalsIgnoreCase("person") || !tag.equalsIgnoreCase("location")){
throw new IllegalArgumentException("Tag types can only be location or person");
}else if(results.size() == 0) {
throw new IllegalArgumentException("No results");
}else {
Intent intent = new Intent(HomeScreen.this,SearchResults.class);
startActivity(intent);
}
} catch(Exception e) {
dialog.dismiss();
Utilities.createErrorDialog(HomeScreen.this, e.getMessage());
}
}
});
searchDialog.show();
}
這裏是XML:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/search_dialog"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:orientation="vertical" >
<TextView
android:id="@+id/tagText"
android:padding="7dp"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:textSize="14sp"
android:text="@string/tag" />
<EditText
android:id="@+id/tagField"
android:padding="7dp"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:inputType="text"/>
<TextView
android:id="@+id/valueText"
android:padding="7dp"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:textSize="14sp"
android:text="@string/value" />
<EditText
android:id="@+id/valueField"
android:padding="7dp"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:inputType="text"/>
</LinearLayout>
任何幫助將是非常讚賞。
你是如何發現'tag'是空的?你在哪裏以及如何輸出它? – 2013-05-05 17:55:26