我如何輸入表格作爲數組？

Question

我需要輸入（下面）中的數據文件：

 14  16  18  20  22  24   
     27  30  35  40  45  50 

     8   10  11  12  13  14   
     16  18  21  24  27  30 

     0.4  0.5  0.5  0.5  0.5  0.5   
     0.6  0.6  0.6  0.6  0.6  0.6 

     16  17  18  19  20  21   
     22  23  25  26  27  29 

     2.0  2.2  2.2  2.3  2.4  2.5   
     2.6  2.7  2.8  2.9  3.1  3.2 

     1.7  1.8  2.0  2.2  2.4  2.5   
     2.8  3.0  3.4  3.8  3.8  3.8 

，其中，選擇一列時，這些瓦萊斯將被輸出。

這是我的代碼;任何人都能看到任何錯誤？

void TimberType() { 

    ifstream inFile; 
    inFile.open("TableOfValues.txt", ios::in); 
    string TimberValues; 
    inFile >> TimberValues; 
    inFile >> bendStr >> tensPara >> tensPerp >> compPara >> compPerp >> shear >> mElasModPara >> elasMod5Para >> mElasModPerp >> mShearMod >> density >> mDensity; 


    cout << "Please enter timber type " << endl; 
    cout << "C14 = 1  C16 = 2  C18 = 3  C20 = 4" << endl; 
    cout << "C22 = 5  C24 = 6  C27 = 7  C30 = 8" << endl; 
    cout << "C35 = 9  C40 = 10 C45 = 11 C50 = 12" << endl; 
    cin >> timberType; 

    { 
     switch (timberType) { 
     case 1: 
      timberType = 1; 
      cout << "You have selected timber type C14" << endl; 
      cout << TimberValues[1]; 
      break; 
     case 2: 
      timberType = 2; 
      cout << "You have selected timber type C16" << endl; 
      cout << TimberValues[2]; 
      break; 
     case 3: 
      timberType = 3; 
      cout << "You have selected timber type C18" << endl; 
      cout << TimberValues[3]; 
      break; 
     case 4: 
      timberType = 4; 
      cout << "You have selected timber type C20" << endl; 
      cout << TimberValues[4]; 
      break; 
     case 5: 
      timberType = 5; 
      cout << "You have selected timber type C22" << endl; 
      cout << TimberValues[5]; 
      break; 
     case 6: 
      timberType = 6; 
      cout << "You have selected timber type C24" << endl; 
      cout << TimberValues[6]; 
      break; 
     case 7: 
      timberType = 7; 
      cout << "You have selected timber type C27" << endl; 
      cout << TimberValues[7]; 
      break; 
     case 8: 
      timberType = 8; 
      cout << "You have selected timber type C30" << endl; 
      cout << TimberValues[8]; 
      break; 
     case 9: 
      timberType = 9; 
      cout << "You have selected timber type C35" << endl; 
      cout << TimberValues[9]; 
      break; 
     case 10: 
      timberType = 10; 
      cout << "You have selected timber type C40" << endl; 
      cout << TimberValues[10]; 
      break; 
     case 11: 
      timberType = 11; 
      cout << "You have selected timber type C45" << endl; 
      cout << TimberValues[11]; 
      break; 
     case 12: 
      timberType = 12; 
      cout << "You have selected timber type C50" << endl; 
      cout << TimberValues[12]; 
      break; 

     } 

     cout << "Bending Strength: " << bendStr << "N/mm^2" << endl; 
     cout << "Tension in Parallel: " << tensPara << "N/mm^2" << endl; 
     cout << "Tension in Perpendicular: " << tensPerp << "N/mm^2" << endl; 
     cout << "Compression in Parallel: " << compPara << "N/mm^2" << endl; 
     cout << "Compression in Perpendicular: " << compPerp << "N/mm^2" << endl; 
     cout << "Shear: " << shear << "N/mm^2" << endl; 

    } 
} 

在我剛剛收到了垂直和剪切彎曲強度，張力並行，張力垂直，壓縮並行，壓縮0值的時刻。

任何想法將不勝感激。謝謝。

Answer 1

爲簡單起見，您可以使用數組將數值讀入 const int ROW = 12，COL = 6; int table [ROW] [COL] = {}; istream文件（「TablesOfValues.txt」）;

for(int i = 0; i < ROW && file; ++i){ 
    for(int j = 0; j < COL && file; ++j){ 
     file >> table[i][j]; 
    } 
} 

//now tables[0][0] = 14 
//now tables[1][2] = 35 
//added a slash to first comment 

Answer 2

 #include <iostream> 
     #include <array> 

     string elem[12][7] = { 
     //First column is the row number (assuming they're related to timber so starting at 1) 
     // Please note these are strings 
     { "1", "14", "16", "18", "20", "22", "24" } 
     { "2", "27", "30", "35", "40", "45", "50" } 
     { "3", "8", "10", "11", "12", "13", "14" } 
     { "4", "16", "18", "21", "24", "27", "30" } 
     { "5", "0.4", "0.5", "0.5", "0.5", "0.5", "0.5" } 
     { "6", "0.6", "0.6", "0.6", "0.6", "0.6", "0.6" } 
     { "7", "16", "17", "18", "19", "20", "21" } 
     { "8", "22", "23", "25", "26", "27", "29" } 
     { "9", "2.0", "2.2", "2.2", "2.3", "2.4", "2.5" } 
     { "10", "2.6", "2.7", "2.8", "2.9", "3.1", "3.2" } 
     { "11", "1.7", "1.8", "2.0", "2.2", "2.4", "2.5" } 
     { "12", "2.8", "3.0", "3.4", "3.8", "3.8", "3.8" } 
     } 

    void TimberType() 
     { 
      ifstream inFile; 
      inFile.open ("TableOfValues.txt", ios :: in); 
      string TimberValues; 
      inFile>>TimberValues; 
      inFile>>bendStr>>tensPara>>tensPerp>>compPara>>compPerp>>shear>>mElasModPara>>elasMod5Para>>mElasModPerp>>mShearMod>>density>>mDensity; 


      cout << "Please enter timber type " << endl; 
      cout << "C14 = 1  C16 = 2  C18 = 3  C20 = 4" << endl; 
      cout << "C22 = 5  C24 = 6  C27 = 7  C30 = 8" << endl; 
      cout << "C35 = 9  C40 = 10 C45 = 11 C50 = 12" << endl; 
      cin >> timberType; 

     { 
      switch (timberType) 
      { 
      case 1: 
       timberType = 1; 
       cout << "You have selected timber type C14" << endl; 
       cout << TimberValues [1]; 
       break; 
      case 2: 
       timberType = 2; 
       cout << "You have selected timber type C16" << endl; 
       cout << TimberValues [2]; 
       break; 
      case 3: 
       timberType = 3; 
       cout << "You have selected timber type C18" << endl; 
       cout << TimberValues [3]; 
       break; 
      case 4: 
       timberType = 4; 
       cout << "You have selected timber type C20" << endl; 
       cout << TimberValues [4]; 
       break; 
      case 5: 
       timberType = 5; 
       cout << "You have selected timber type C22" << endl; 
       cout << TimberValues [5]; 
       break; 
      case 6: 
       timberType = 6; 
       cout << "You have selected timber type C24" << endl; 
       cout << TimberValues [6]; 
       break; 
      case 7: 
       timberType = 7; 
       cout << "You have selected timber type C27" << endl; 
       cout << TimberValues [7]; 
       break; 
      case 8: 
       timberType = 8; 
       cout << "You have selected timber type C30" << endl; 
       cout << TimberValues [8]; 
       break; 
      case 9: 
       timberType = 9; 
       cout << "You have selected timber type C35" << endl; 
       cout << TimberValues [9]; 
       break; 
      case 10: 
       timberType = 10; 
       cout << "You have selected timber type C40" << endl; 
       cout << TimberValues [10]; 
       break; 
      case 11: 
       timberType = 11; 
       cout << "You have selected timber type C45" << endl; 
       cout << TimberValues [11]; 
       break; 
      case 12: 
       timberType = 12; 
       cout << "You have selected timber type C50" << endl; 
       cout << TimberValues [12]; 
       break; 

      } 

// This is the code you need to edit to search the array 

void searchString(string A[],int size, string target) 
{ 
    int j; 
    { 
    for(j=0; j < size; j++) 
     if(A[j] == target) 
      cout << A[j] << endl; 
     else cout << "Not Found"; 
    } 
} 


      cout << "Bending Strength: "<< bendStr << "N/mm^2" << endl; 
      cout << "Tension in Parallel: "<< tensPara << "N/mm^2" << endl; 
      cout << "Tension in Perpendicular: "<< tensPerp << "N/mm^2" <<endl; 
      cout << "Compression in Parallel: "<< compPara << "N/mm^2" << endl; 
      cout << "Compression in Perpendicular: "<< compPerp << "N/mm^2" << endl; 
      cout << "Shear: "<< shear << "N/mm^2" << endl; 

     } 
     } 

I believe there is a simple search command that will let you reference the timber numbers based on their number. Please post the final code here because I'm actually working on something like this and would love to know how it worked for you. 

Answer 3

以下是一些建議：
更換switch與查表：

struct Timber_Text_Entry 
{ 
    unsigned int index; 
    char const text; 
}; 

const Timber_Text_Entry Timber_Type_Names[] = 
{ 
    { 1, "C14"}, { 2, "C16"}, {3, "C18"}, {4, "C20"}, 
//... 
}; 
const unsigned int NUMBER_OF_TIMBER_TYPES = 
    sizeof(Timber_Type_Names)/sizeof(Timber_Type_Names[0]); 

// Printing the menu contents: 
for (unsigned int i = 0; i < NUMBER_OF_TIMBER_TYPES; ++i) 
{ 
    cout << Timber_Type_Names[i].text 
     << " = " 
     << Timber_Type_Names[i].index; 
    if ((i % 4) == 3) cout << "\n"; 
} 

// The switch statement replaced: 
if ((timberType > 1) && (timberType <= NUMBER_OF_TIMBER_TYPES)) 
{ 
    // This should search for the index == timberType instead 
    // of using timberType as an index into the array. 
    // The code below assumes the order of the entries will 
    // not change. 
    // The "-1" is because timberTypes start at 1 and the 
    // array indices start at 0. 
    cout << "You have selected timber type "; 
    cout << Timber_Type_Names[timberType - 1].text; 
    cout << endl; 
} 
else 
{ 
    cout << "Invalid timber selection: " << timberType << endl; 
}