提取參數

Question

我有這樣

String pattern = "Send {{message}} to {{name}}"; 

字符串模式比我有這樣一個

String sentence = "Send Hi there to Jesus"; 

一句我想是與模式匹配句子和返回的東西像一個 JsonObject，它有以下句子的參數：

{"message": "Hi there", "name": "Jesus"} 

有沒有簡單的解決方案呢？

Answer 1

該單元測試通過引用匹配組（通過括號括起的圓括號）通過組索引來提取句子內容。如果模式匹配給定字符串，則整個輸入字符串爲組0.在給定示例中，匹配的message位於組索引1，name位於索引2.或者，您可以定義命名組。

@RunWith(Parameterized.class) 
public class Snippet { 

    private final String testSentence; 
    private final String[][] expectedResult; 



    public Snippet(String testSentence, String[][] expectedMessages) { 
     this.testSentence = testSentence; 
     this.expectedResult = expectedMessages; 
    } 

    private String[][] extractSentenceContent(String sentence) { 
     Pattern pattern = Pattern.compile("Send\\s([\\p{Alpha}\\s]+)\\sto\\s([\\p{Alpha}\\s]+)"); 
     Matcher matcher = pattern.matcher(sentence); 

     String[][] result; 

     if(matcher.matches()) { 
      result = new String[][] {{"message", matcher.group(1)}, {"name", matcher.group(2)}}; 
     } else { 
      result = null; 
     } 
     return result; 
    } 

    @Test 
    public void testRegex(){ 

     String[][] actualResult = extractSentenceContent(testSentence); 

     TestCase.assertTrue(Arrays.deepEquals(expectedResult, actualResult)); 
    } 



    @Parameters 
    public static Iterable<?> getTestParameters(){ 

     Object[][] parameters = { 
       {"Send Hi there to Jesus", new String[][] {{"message", "Hi there"}, {"name", "Jesus"}}} 
     }; 
     return Arrays.asList(parameters); 
    } 
} 

有沒有辦法從模板， 得到捕獲組名稱沒有硬編碼「消息」和「名」？

一個特設的解決辦法是使用String.format插入這樣的動態捕捉組名稱：

private String[][] extractSentenceContent(String sentence, String captureGroupA, String captureGroupB) { 
    String pattern = String.format("^Send\\s(?<%s>[\\p{Alpha}\\s]+)\\sto\\s(?<%s>[\\p{Alpha}\\s]+)$", captureGroupA, captureGroupB); 

    Matcher matcher = Pattern.compile(pattern).matcher(sentence); 

    String[][] result; 

    if(matcher.matches()) { 
     result = new String[][] { 
      {captureGroupA, matcher.group(captureGroupA)}, 
      {captureGroupB, matcher.group(captureGroupB)} 
     }; 
    } else { 
     result = null; 
    } 
    return result; 
} 

Answer 2

i= sentence.length(); 

while(sentence[i] != " "){ 
    i--; 
} 

i++; 

for(intj=0;j<i;j++) 
    name[j]= sentence[j]; 
} 

for(int k = 5;k<(sentence.length()-i-3);k++){ 
    message[k] = sentence[k]; 
}