如何獲得一個函數來執行，直到條件不充分

Question

import copy  
def remove_fully_correct(answer, guess): 
     """(list,list) -> list 
     Return a list that removes the chars from the first list that are the same and in the same position in the second list 
     >>>remove_fully_correct(['a','b','c','d'], ['d','b','a','d']) 
     ['a','c'] 
     """ 
     res = copy.copy(answer) 
     for index in range(len(res)): 
      for x, y in zip(res, guess): 
       if res[index] == guess[index]: 
        res.remove(x) 
       return res 

基本上我有一個功能，刪除所有從一個列表在第二列表中找到的人物，但我的功能似乎只刪除第一個值從列表中找到。任何幫助表示讚賞

Answer 1

你是內環路返回，所以你只能有一個通過外循環：

import copy  
def remove_fully_correct(answer, guess): 
     """(list,list) -> list 
     Return a list that removes the chars from the first list that are the same and in the same position in the second list 
     >>>remove_fully_correct(['a','b','c','d'], ['d','b','a','d']) 
     ['a','c'] 
     """ 
     res = copy.copy(answer) 
     for index in range(len(res)): 
      for x, y in zip(res, guess): 
       if res[index] == guess[index]: 
        res.remove(x) 
     return res # move outside 

您應該使用枚舉，如果列表大小都一樣：

def remove_fully_correct(answer, guess): 
     """(list,list) -> list 
     Return a list that removes the chars from the first list that are the same and in the same position in the second list 
     >>>remove_fully_correct(['a','b','c','d'], ['d','b','a','d']) 
     ['a','c'] 
     """ 
     return [ele for index,ele in enumerate(answer) if ele != guess[index]] 


In [6]: remove_fully_correct(['a','b','c','d'], ['d','b','a','d']) 
Out[6]: ['a', 'c'] 

使用zip：

def remove_fully_correct(answer, guess): 
     """(list,list) -> list 
     Return a list that removes the chars from the first list that are the same and in the same position in the second list 
     >>>remove_fully_correct(['a','b','c','d'], ['d','b','a','d']) 
     ['a','c'] 
     """ 
     return [a for a,b in zip(answer,guess) if a != b]