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我想在django中進行「上下文」表單驗證。考慮這種情況下:Django中的上下文表單驗證
PLACE_TYPES = (
('RESTAURANT', 'Restaurant'),
('BARCLUB', 'Bar/Club'),
('SHOPPING', 'Shopping'),
)
RESTAURANT_FORMAT_CHOICES = (
('FAST_FOOD', 'Fast Food'),
('FAST_CASUAL', 'Fast Casual'),
('CASUAL', 'Casual'),
('CHEF_DRIVEN', 'Chef Driven'),
)
class Place(models.Model):
place_type = models.CharField(max_length=48, choices=PLACE_TYPES, blank=False, null=False)
name = models.CharField(max_length=256)
website_1 = models.URLField(max_length=512, blank=True)
hours = models.CharField(max_length=1024, blank=True)
geometry = models.PointField(srid=4326, blank=True, null=True)
#Restaurant Specific
restaurant_format = models.CharField(max_length=128, choices=RESTAURANT_FORMAT_CHOICES, blank=True, null=True)
所以在Django管理,用於放置相應的形式將有下拉菜單中包含「餐廳,酒吧,俱樂部」的選擇,有一個名爲「restaurant_format」另一個領域。
驗證應確保restaurant_field不能爲空,如果第一個下拉菜單設置爲「餐廳」。
我想是這樣的:
class PlaceAdminForm(forms.ModelForm):
def clean(self):
if self.cleaned_data['place_type'] == 'RESTAURANT':
if self.cleaned_data['place_type'] is None:
raise forms.ValidationError('For a restaurant you must choose a restaurant format')
,但得到這個錯誤:
異常類型:KeyError異常 異常值:
place_type
異常位置:/地點/管理。 py in clean,line 27