你可以使用strings.IndexRune
,strings.IndexByte
,strings.Split
,strings.SplitAfter
,strings.FieldsFunc
,url.Parse
,regexp
或你的函數。
第一個最簡單的方法:
你可以使用i := strings.IndexRune(s, '?')
或i := strings.IndexByte(s, '?')
然後s[:i]
像這樣(註釋輸出):
package main
import "fmt"
import "strings"
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
i := strings.IndexByte(s, '?')
if i != -1 {
fmt.Println(s[:i]) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
}
,或者您可以使用url.Parse(s)
(我用這個):
package main
import "fmt"
import "net/url"
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
url, err := url.Parse(s)
if err == nil {
url.RawQuery = ""
fmt.Println(url.String()) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
}
或者您可以使用regexp.MustCompile(".*\\.txt")
:
package main
import "fmt"
import "regexp"
var rgx = regexp.MustCompile(`.*\.txt`)
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
fmt.Println(rgx.FindString(s)) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
,或者您可以使用splits := strings.FieldsFunc(s, func(r rune) bool { return r == '?' })
然後splits[0]
:
package main
import "fmt"
import "strings"
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
splits := strings.FieldsFunc(s, func(r rune) bool { return r == '?' })
fmt.Println(splits[0]) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
您可以使用splits := strings.Split(s, "?")
然後splits[0]
:
package main
import "fmt"
import "strings"
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
splits := strings.Split(s, "?")
fmt.Println(splits[0]) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
您可以使用splits := strings.SplitAfter(s, ".txt")
然後splits[0]
:
package main
import "fmt"
import "strings"
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
splits := strings.SplitAfter(s, ".txt")
fmt.Println(splits[0]) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
,或者你可以使用你的功能(最獨立的方式):
package main
import "fmt"
func left(s string) string {
for i, r := range s {
if r == '?' {
return s[:i]
}
}
return ""
}
func main() {
s := `https://example-1.example.com/a/c482dfad3573acff324c/list.txt?parm1=value,parm2=value,parm3=https://example.com/a?parm1=value,parm2=value`
fmt.Println(left(s)) // https://example-1.example.com/a/c482dfad3573acff324c/list.txt
}
我推薦使用的url.Parse由於應該處理任何奇怪的邊緣的情況下這可能會被正則表達式或分割錯過。例如,沒有?的URL? –
我同意url.Parse是最好的方法。列出的所有選項都處理沒有'?'的URL。 –