我也跟着教程做的是iOS計算器,和我現在想要一個小數位按鈕添加到它。這裏是我的代碼添加一個小數點按鈕到iOS計算器
頭文件:
#import <UIKit/UIKit.h>
@interface CalcViewController : UIViewController {
float result;
float selectedNumber;
int selectedOperation;
IBOutlet UILabel *calcScreen;
}
-(IBAction)numberPressed:(id)sender;
-(IBAction)operationPressed:(id)sender;
-(IBAction)clearNumber:(id)sender;
-(IBAction)clearOperation:(id)sender;
@end
這是我實現文件
#import "CalcViewController.h"
@implementation CalcViewController
-(IBAction)numberPressed:(id)sender {
selectedNumber = selectedNumber * 10 + (float) [sender tag];
calcScreen.text = [NSString stringWithFormat:@"%2g", selectedNumber];
}
-(IBAction)operationPressed:(id)sender {
if (selectedOperation == 0) {
result = selectedNumber;
} else {
switch (selectedOperation) {
case 1:
result = result + selectedNumber;
break;
case 2:
result = result - selectedNumber;
break;
case 3:
result = result * selectedNumber;
break;
case 4:
result = result/selectedNumber;
break;
case 5:
selectedOperation = 0;
break;
}
}
selectedNumber = 0;
calcScreen.text = [NSString stringWithFormat:@"%2g", result];
if ([sender tag] == 0) result = 0;
selectedOperation = [sender tag];
}
-(IBAction)clearNumber:(id)sender {
selectedNumber = 0;
calcScreen.text = @"0";
}
-(IBAction)clearOperation:(id)sender {
selectedNumber = 0;
calcScreen.text = @"0";
selectedOperation = 0;
}
我在另一個線程,有人使用方法提示看到:
- (IBAction)Decimal:(id)sender
{
NSString *currentText = calcScreen.text;
if ([currentText rangeOfString:@"." options:NSBackwardsSearch].length == 0) {
calcScreen.text = [calcScreen.text stringByAppendingString:@"."];
}
然而,這似乎並不適用於我。它的確會讓我輸入小數點,但是當輸入第二個數字時,小數點會丟失。任何人都可以提出一個我可以實現的方法來實現我想要的嗎?
乾杯提前!
因此具有u發現這個問題的任何解決方案? – lakesh 2012-10-29 16:56:11