Lua - 涉及string.gsub的加密邏輯錯誤，加密輸出不是輸入

Question

我的程序似乎遇到了邏輯錯誤。我已經多次查看它，甚至編寫了與此類似的另一個程序（似乎也有相同的錯誤）。我無法弄清楚什麼是錯的，但我認爲它可能涉及我string.gsub的使用...

repeat 
local file = io.open("out.txt", "w") 
print("would you like to translate Cipher to English or English to Cipher?") 
print("enter 1 for translation to English. enter 2 for translation to Cipher") 
tchoice=io.read() 
if tchoice=="2" then 
print(" enter any text to translate it: ") 
rawtextin=io.read() 
text=string.lower(rawtextin) 
text1=string.gsub(text,"a","q") 
text2=string.gsub(text1,"b","e") 
text3=string.gsub(text2,"c","h") 
text4=string.gsub(text3,"d","c") 
text5=string.gsub(text4,"e","j") 
text6=string.gsub(text5,"f","m") 
text7=string.gsub(text6,"g","r") 
text8=string.gsub(text7,"h","g") 
text9=string.gsub(text8,"i","b") 
text10=string.gsub(text9,"j","a") 
text11=string.gsub(text10,"k","d") 
text12=string.gsub(text11,"l","y") 
text13=string.gsub(text12,"m","v") 
text14=string.gsub(text13,"n","z") 
text15=string.gsub(text14,"o","x") 
text16=string.gsub(text15,"p","k") 
text17=string.gsub(text16,"q","i") 
text18=string.gsub(text17,"r","l") 
text19=string.gsub(text18,"s","f") 
text20=string.gsub(text19,"t","s") 
text21=string.gsub(text20,"u","w") 
text22=string.gsub(text21,"v","t") 
text23=string.gsub(text22,"w","p") 
text24=string.gsub(text23,"x","u") 
text25=string.gsub(text24,"y","n") 
text26=string.gsub(text25,"z","o") 
text27=string.gsub(text26," ","@") 
print(text27) 
elseif tchoice=="1" then 
print("enter text!") 
rawtextin=io.read() 
text=string.lower(rawtextin) 
text1=string.gsub(text,"q","a") 
text2=string.gsub(text1,"e","b") 
text3=string.gsub(text2,"h","c") 
text4=string.gsub(text3,"c","d") 
text5=string.gsub(text4,"j","e") 
text6=string.gsub(text5,"m","f") 
text7=string.gsub(text6,"r","g") 
text8=string.gsub(text7,"g","h") 
text9=string.gsub(text8,"b","i") 
text10=string.gsub(text9,"a","j") 
text11=string.gsub(text10,"d","k") 
text12=string.gsub(text11,"y","l") 
text13=string.gsub(text12,"v","m") 
text14=string.gsub(text13,"z","n") 
text15=string.gsub(text14,"x","o") 
text16=string.gsub(text15,"k","p") 
text17=string.gsub(text16,"i","q") 
text18=string.gsub(text17,"l","r") 
text19=string.gsub(text18,"f","s") 
text20=string.gsub(text19,"s","t") 
text21=string.gsub(text20,"w","u") 
text22=string.gsub(text21,"t","v") 
text23=string.gsub(text22,"p","w") 
text24=string.gsub(text23,"u","x") 
text25=string.gsub(text24,"n","y") 
text26=string.gsub(text25,"o","z") 
text27=string.gsub(text26,"@"," ") 
print(text27) 
end 
print("writing to out.txt...") 
file:write(text27) 
file:close() 
print("done!") 
print("again? type y for yes or anything else for no.") 
again=io.read() 
until again~="y" 
x=io.read() 

在代碼中沒有錯誤 - 我在想什麼？我意識到這不是最有效的方法，但我需要弄清楚在使用循環和表編寫更高效的程序之前出了什麼問題。

樣品運行（只有顯著數據附帶）：

Answer 1

local decoded = 'abcdefghijklmnopqrstuvwxyz @' 
local encoded = 'qehcjmrgbadyvzxkilfswtpuno@ ' 

local enc, dec = {}, {} 
for i = 1, #decoded do 
    local e, d = encoded:sub(i,i), decoded:sub(i,i) 
    enc[d] = e 
    dec[e] = d 
end 

repeat 
    local file = io.open("out.txt", "w") 
    local text27, rawtextin 
    print("would you like to translate Cipher to English or English to Cipher?") 
    print("enter 1 for translation to English. enter 2 for translation to Cipher") 
    local tchoice = io.read() 
    if tchoice == "2" then 
     print(" enter any text to translate it: ") 
     rawtextin = io.read() 
     text27 = rawtextin:lower():gsub('.',enc) 
     print(text27) 
    elseif tchoice == "1" then 
     print("enter text!") 
     rawtextin = io.read() 
     text27 = rawtextin:lower():gsub('.',dec) 
     print(text27) 
    end 
    print("writing to out.txt...") 
    file:write(text27) 
    file:close() 
    print("done!") 
    print("again? type y for yes or anything else for no.") 
    local again = io.read() 
until again ~= "y"