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我目前正在通過Java Deadlock Tutorial工作並瞭解程序示例總是會遇到死鎖。Lambda表達式是否可以解決死鎖問題?
public class Deadlock
{
private static class Friend
{
private final String name;
public Friend(String name) { this.name = name; }
public String getName() {return name;}
public synchronized void bow(Friend bower)
{
System.out.format("%s: %s has bowed to me!%n", this.name, bower.getName());
bower.bowBack(this);
}
public synchronized void bowBack(Friend bower)
{
System.out.format("%s: %s has bowed back to me!%n", this.name, bower.getName());
}
}
public static void main(String[]args)
{
final Friend alphonse = new Friend("alphonse");
final Friend gaston = new Friend("gaston");
new Thread(new Runnable(){
@Override
public void run()
{
alphonse.bow(gaston);
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
gaston.bow(alphonse);
}
}).start();
}
}
當我更換一個合適的lambda表達式線程實例之一:new Thread(() -> gaston.bow(alphonse)).start();
這似乎解決死鎖問題。但是當兩個線程實例化都被lambdas替換時,程序又會死鎖。
背後有一個原因嗎?