Python從列表中返回唯一字（不區分大小寫）

Question

我需要幫助從列表中順序返回唯一字（不區分大小寫）。

例如：

def case_insensitive_unique_list(["We", "are", "one", "we", "are", "the", "world", "we", "are", "THE", "UNIVERSE"]) 

返回結果： [ 「我們」， 「是」， 「一」， 「中」， 「世界」， 「宇宙」]

到目前爲止，是我有什麼：

def case_insensitive_unique_list(list_string): 

uppercase = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"] 
lowercase = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] 

temp_unique_list = [] 

for i in list_string: 
    if i not in list_string: 
     temp_unique_list.append(i) 

我有每個人的話從是否重演的還是不說一句話temp_unique_list比較麻煩。例如：「來」和「To」（我假設範圍功能將是有益的）

，並使其返回首先來自該功能將在原始列表中字

會有怎樣。我這樣做使用for循環？

Answer 1

您可以用for環和set數據結構的幫助下做到這一點，像這樣

def case_insensitive_unique_list(data): 
    seen, result = set(), [] 
    for item in data: 
     if item.lower() not in seen: 
      seen.add(item.lower()) 
      result.append(item) 
    return result 

輸出

['We', 'are', 'one', 'the', 'world', 'UNIVERSE'] 

Answer 2

你能做到這一點的：

l = ["We", "are", "one", "we", "are", "the", "world", "we", "are", "THE", "UNIVERSE"] 

a = [] 

for i in l: 
    if i.lower() not in [j.lower() for j in a]: 
     a.append(i) 

>>> print a 
['We', 'are', 'one', 'the', 'world', 'UNIVERSE'] 

Answer 3

您可以使用set()和列表理解：

>>> seen = set() 
>>> lst = ["We", "are", "one", "we", "are", "the", "world", "we", "are", "THE", "UNIVERSE"] 
>>> [x for x in lst if x.lower() not in seen and not seen.add(x.lower())] 
['We', 'are', 'one', 'the', 'world', 'UNIVERSE'] 

Answer 4

l=["We", "are", "one", "we", "are", "the", "world", "we", "are", "THE", "UNIVERSE"] 
so=[] 
for w in l: 
    if w.lower() not in so: 
     so.append(w.lower()) 

In [14]: so 
Out[14]: ['we', 'are', 'one', 'the', 'world', 'universe'] 

Answer 5

您可以使用一組，以確保其唯一性。當你嘗試添加一個重複項目到一個集合時，它會簡單地丟棄它，如果它已經在那裏。

您還應該使用in-built lower（）函數來管理不區分大小寫。

uniques = set() 
for word in words: 
    set.add(word.lower()) #lower it first and then add it 

如果這是一門功課的任務，並使用一套是關閉的限制，那麼你可以很容易地適應它通過只使用名單，只是循環並添加條件：

uniques = list() 
if word.lower() not in uniques: 
    #etc 

Answer 6

OK，去除我之前的回答，因爲我誤解了OP的帖子。我所有的道歉。

爲藉口，爲它的樂趣，並以不同的方式做這件事的緣故，這裏的另一種解決方案，儘管它既不是最有效的一個，或最好：

>>> from functools import reduce 
>>> for it in reduce(lambda l,it: l if it in set({i.lower() for i in l}) else l+[it], lst, []): 
...  print(it, end=", ") 

Answer 7

您可以使用collections.OrderedDict喜歡這個。

from collections import OrderedDict 
def case_insensitive_unique_list(data): 
    d = OrderedDict() 
    for word in data: 
     d.setdefault(word.lower(), word) 
    return d.values() 

輸出：

['We', 'are', 'one', 'the', 'world', 'UNIVERSE']