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我正在創建數據分析儀表板。我將一個名爲channel_param
的參數傳遞給MySQL數據源。基於mySQL IF-ELSE條件選擇兩個MySQL select查詢
我想補充的,如果在這個查詢語句首先檢查channel_param參數值等於「ALL」
在「ALL」的情況下,下面的查詢應執行:
SELECT
c.CountryCode, COUNT(f.`country_code_id`) AS view_count
FROM
fact_access_logs_views f
JOIN dim_country_code c ON f.`country_code_id` = c.`country_code_id`
JOIN dim_time_access d ON f.`access_time_id` = f.`access_time_id`
JOIN dim_channel chn ON f.`channel_id` = chn.`channel_id
在任何其他價值的情況下,該查詢應執行:
SELECT
c.CountryCode, COUNT(f.`country_code_id`) AS view_count
FROM
fact_access_logs_views f
JOIN dim_country_code c ON f.`country_code_id` = c.`country_code_id`
JOIN dim_time_access d ON f.`access_time_id` = f.`access_time_id`
JOIN dim_channel chn ON f.`channel_id` = chn.`channel_id`
WHERE
chn.`shortname_chn` = ${channel_param}
我怎樣才能做到這一點?
Mysql確實有IF()[refrence](http://stackoverflow.com/a/15265944/2586617) –