使用laravel 5.2得到錯誤

蔭全光照MySQL的5.7，在我的申請laravel5.2和PHP 5.6.17 ..在MySQL 5.7從JSON列類型檢索JSON數據時使用laravel 5.2得到錯誤

我創建遷移表

public function up() 
    { 
     Schema::create('admin_login_history', function (Blueprint $table) { 
      $table->increments('id'); 
      $table->string('url'); 
      $table->json('client_details'); 
      $table->integer('user_id')->nullable(); 
      $table->timestamps(); 
     }); 
    }

我創建了它的模型..

class AdminLoginHistory extends Model 
{ 

    protected $table = 'admin_login_history'; 

    protected $fillable = ['file_path', 'url', 'user_id', 'client_details']; 

    protected $casts = ['client_details' => 'json']; 
}

蔭插入其換算爲JSON在我的模型client_details的數據的數組。

現在檢索時從表中IAM的數據得到錯誤

$loginhistory = AdminLoginHistory::where('user_id', $id)->orderBy('created_at', 'desc')->take(3)->get();

錯誤：

File Path: /home/storage/elivio/InvizoAdmin/vendor/laravel/framework/src/Illuminate/Database/Connection.php 
Error Code:HY000, Line Number:669 
Message:SQLSTATE[HY000]: General error: 2036 (SQL: select * from `admin_login_history` where `user_id` = 1 order by `created_at` desc limit 3)

來源

2016-03-22 Veerendra Borra