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我在嘗試獲取關聯表中保存的數據時遇到問題（當前保存時只保存在初始表中，而不保存在其他表中）。CakePHP 3.x - 在多個表中保存關聯的數據
所以我的第一個表（用戶）：
-id
-username
-password
-email
二表（藝術家）：
-name
-cp_id (foreign key)
-user_id (foreign key)
-genre
三表（Contactpersons）：
-cp_firstname
-cp_lastname
-cp_email
-cp_phoneno
關係：
A User hasOne Artist. An Artist belongsTo a User. (1-1)
An Artist belongsTo Contactperson. A Contactperson hasMany Artists (1 to many)
user_id in Artists references id in Users
cp_id in Artists references id in Contactpersons
在我UsersController：
public function artistregister()
{
$user = $this->Users->newEntity();
if($this->request->is('post')){
$data = $this->request->data;
$data['role_id'] = "2"; //role_id 2 makes the user register as role = artist
$user = $this->Users->patchEntity($user, $data);
$save = $this->Users->save($user);
if ($save) {
$user_id = $save->id;
$data['user_id'] = $user_id;
$ContactPersonsController = new ContactPersonsController();
$ContactPersonsController->artistregister($data);
$ArtistController = new ArtistsController();
$ArtistController->artistregister($data);
$this->Flash->success(__('Registration completed'));
return $this->redirect(['action' => 'login']);
} else {
$this->Flash->error(__('Registration failed. Please try again.'));
}
}
$artists = $this->Users->Artists->find('all');
$persons = $this->Users->Artists->ContactPersons->find('all')->toArray();
$this->set(compact('user', 'artists', 'roles', 'contactpersons','persons'));
$this->set('_serialize', ['user']);
}
然後在Contactpersons控制器，相同的功能：
public function artistregister($data)
{
if ($this->Contactpersons)
$contactperson = $this->Contactpersons->newEntity();
$contactperson = $this->Contactpersons->patchEntity($contactperson, $data);
if ($this->Contactpersons->save($contactperson)) {
$this->Flash->error(__('Contact person details could not be saved. Please try again.'));
}
$this->set(compact('contactpersons'));
$this->set('_serialize', ['contactperson']);
}
而且ArtistsController，再次相同的功能：
public function artistregister($data)
{
$artist = $this->Artists->newEntity();
$user = $this->request->session()->read('Auth.User');
$data['user_id'] = $user['id'];
$contactperson = $this->request->session()->read('Auth.Contactpersons') //I put in Auth.Contactpersons as a placeholder, but I'm not really sure what to put there.
$data['cp_id'] = $contactperson['id'];
$artist = $this->Artists->patchEntity($artist, $data);
if ($this->Artists->save($artist)) {
$this->Flash->error(__('Artist profile details could not be saved. Please try again.'));
}
$contactpersons = $this->Artists->Contactpersons->find('list', ['limit' => 200]);
$this->set(compact('artist', 'contactpersons'));
$this->set('_serialize', ['artist']);
}
哦，對好的措施，這裏的Artistregister.ctp文件：
<div class="container" style="margin-top: 70px;">
<?= $this->Flash->render('auth') ?>
<?php $this->Form->templates([
'inputContainer' => '<div class="form-group">{{content}}</div>',
'inputContainerError' => '<div class="error" style="color:red;">{{content}}{{error}}</div>'
]);?>
<div class="col-sm-2">
</div>
<div class="col-sm-8">
<div class="container col-sm-12" style="border-radius: 10px; border: 1px solid;" >
<?= $this->Form->create($user, ['role'=>'form']) ?>
<header><?= __('Artist Registration') ?></header>
<legend><?= __('User Account Details') ?></legend>
<div class="col-sm-6">
<?= $this->Form->input('username', ['class'=>'form-control',
'placeholder'=>'Please enter a username.']);?>
</div>
<div class="col-sm-6">
<?= $this->Form->input('email', ['class'=>'form-control', 'type'=>'email',
'placeholder'=>'Please enter an email address.']);?>
</div>
<div class="col-sm-6">
<?= $this->Form->input('password', ['class'=>'form-control', 'type'=>'password',
'placeholder'=>'Please enter a password.']);?>
</div>
<div class="col-sm-6">
<?= $this->Form->input('confirm_password', array('type'=>'password',
'label'=>'Confirm Password', 'value'=>'', 'autocomplete'=>'off','class'=>'form-control',
'placeholder'=>'Please re-enter your password.'))?>
</div>
<legend><?= __('Artist Profile Details') ?></legend>
<div class="col-sm-12">
<?= $this->Form->input('name', ['class'=>'form-control', 'label'=>'Artist Name',
'placeholder'=>'Please enter your artist name.']);?>
</div>
<div class="col-sm-12">
<?= $this->Form->input('genre', ['class'=>'form-control', 'type'=>'textarea', 'label'=>'Genres',
'placeholder'=>'Please enter a description of the genres you play.']);?>
</div>
<legend><?= __('Contact Person Details') ?></legend>
<div class="col-sm-6">
<?= $this->Form->input('cp_firstname', ['class'=>'form-control', 'label'=>'First Name',
'placeholder'=>'Please enter the first name of your contact.']);?>
</div>
<div class="col-sm-6">
<?= $this->Form->input('cp_lastname', ['class'=>'form-control', 'label'=>'Last Name',
'placeholder'=>'Please enter the last name of your contact.']);?>
</div>
<div class="col-sm-6">
<?= $this->Form->input('cp_phoneno', ['class'=>'form-control','type'=>'tel', 'label'=>'Phone Number',
'placeholder'=>'Please enter the phone number of your contact.']);?>
</div>
<div class="col-sm-6">
<?= $this->Form->input('cp_email', ['class'=>'form-control','type'=>'email', 'label'=>'Email',
'placeholder'=>'Please enter the email of your contact.']);?>
</div>
<legend></legend>
<div class="col-sm-12" >
<?= $this->Form->button('<strong>'.__('Register').'</strong>',
['class'=>'btn btn-primary', 'style'=>'width:100%;']); ?>
</div>
<div class="col-sm-12" align="center" style="margin-bottom: 20px;">
<?= $this->Html->link(__("Already have an account? Log in"), ['action'=>'logout'])?>
</div>
<?= $this->Form->end() ?>
</div>
</div>
<div class="col-sm-2">
</div>
</div>
因此，當我進入Artistregister頁面時，填寫字段並單擊提交，與Users表相關的所有數據都會提交，但Contactpersons和Artists表保持空白。目前我得到的錯誤是：
Call to undefined method App\Controller\ContactpersonsController::artistregister()
與線回參考點：
$ContactPersonsController->artistregister($data);
。
同時，如果我換被稱爲功能的順序（ContactpersonsController之前即調用ArtistsController），我得到這個錯誤：
syntax error, unexpected '$data' (T_VARIABLE)
與線回參考點：
$data['cp_id'] = $contactperson['id'];
這線在ArtistsController函數中找到。
我很確定我得到這個錯誤，因爲沒有聯繫人存在，因此它找不到一個id作爲cp_id - 這就是爲什麼在UsersController函數中，我首先調用ContactpersonsController來建立一些數據聯繫人表。
添加在模型中的每個：
Contactpersons：
class ContactpersonsTable extends Table
{
public function initialize(array $config)
{
parent::initialize($config);
$this->table('contactpersons');
$this->displayField('id');
$this->primaryKey('id');
}
public function validationDefault(Validator $validator)
{
$validator
->integer('id')
->allowEmpty('id', 'create');
$validator
->requirePresence('cp_firstname', 'create')
->notEmpty('cp_firstname');
$validator
->requirePresence('cp_lastname', 'create')
->notEmpty('cp_lastname');
$validator
->requirePresence('cp_email', 'create')
->notEmpty('cp_email');
$validator
->integer('cp_phoneno')
->requirePresence('cp_phoneno', 'create')
->notEmpty('cp_phoneno');
return $validator;
}
}
藝術家：
class ArtistsTable extends Table
{
public function initialize(array $config)
{
parent::initialize($config);
$this->table('artists');
$this->displayField('name');
$this->primaryKey('id');
$this->addBehavior('Timestamp');
$this->belongsTo('Contactpersons', [
'foreignKey' => 'cp_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Users', [
'foreignKey' => 'user_id',
'joinType' => 'INNER'
]);
$this->hasMany('Bookings', [
'foreignKey' => 'artist_id'
]);
}
public function validationDefault(Validator $validator)
{
$validator
->integer('id')
->allowEmpty('id', 'create');
$validator
->requirePresence('name', 'create')
->notEmpty('name');
$validator
->allowEmpty('genre');
return $validator;
}
public function buildRules(RulesChecker $rules)
{
$rules->add($rules->existsIn(['cp_id'], 'Contactpersons'));
$rules->add($rules->existsIn(['user_id'], 'Users'));
return $rules;
}
}
用戶：
class UsersTable extends Table
{
public function initialize(array $config)
{
parent::initialize($config);
$this->table('users');
$this->displayField('id');
$this->primaryKey('id');
$this->addBehavior('Timestamp');
$this->belongsTo('Roles', [
'foreignKey' => 'role_id',
'joinType' => 'INNER'
]);
$this->hasOne('Artists', [
'foreignKey' => 'user_id'
]);
$this->hasOne('Engineers', [
'foreignKey' => 'user_id'
]);
}
public function validationDefault(Validator $validator)
{
$validator
->integer('id')
->allowEmpty('id', 'create');
$validator
->requirePresence('username', 'create')
->notEmpty('username');
$validator
->requirePresence('password', 'create')
->notEmpty('password');
$validator
->email('email')
->requirePresence('email', 'create')
->notEmpty('email');
return $validator;
}
public function buildRules(RulesChecker $rules)
{
$rules->add($rules->isUnique(['username']));
$rules->add($rules->isUnique(['email']));
$rules->add($rules->existsIn(['role_id'], 'Roles'));
return $rules;
}
}
我現在得到這個錯誤，沒有數據被添加到表中，即使在Users表中：無法封送「ContactPersons」關聯的數據。它不與「用戶」關聯。 InvalidArgumentException（你怎麼在評論中做新行？） – mistaq
發佈你的每個模型 – Derek
現在添加到OP – mistaq