僅獲得使用shell腳本

Question

我試圖得到一個例子工作的文件名：

這裏是我想要做的事：

一）有7個文件的文件夾與名稱和時間戳附加。

示例：Windows_<timestamp>.csv和Linux_<timestamp>.csv等等。

我想先a）將即將重命名的文件重命名爲新文件夾，然後重命名當前文件。

我試過看Rename multiple files by replacing a particular pattern in the filenames using a shell script但該腳本不適合我。我相信我必須在那裏修改一些東西，但我似乎無法得到它的工作。

任何人都可以幫我嗎？我真的被困在這裏。

謝謝！

Answer 1

#!/bin/bash 
# find all the files that are created today and end with an extension. 
# a) First find all the files created today, and filter only the files we care about. 
# b) Move all these files into a new folder. 
# c) Iterate all the files in this new folder. 
# d) Re-name all the files in the destination folder by replacing the _ 
sourceFolderName="/home/abhididdigi/Desktop/TADDM" 
targetFolderName="/home/abhididdigi/Desktop/TADDM_ServiceNow/" 
#find all the files created today and only the CSV ones. 
    find $sourceFolderName -type f -mtime 0 -name '*.csv'| 
    while read filename 
     do 
      # TODO: Find only those files that we care about 
      cp $filename $targetFolderName 

     done 
    #targetFileName=${filename%_*}|sed 's#.*/##'; 
    #Rename the files now, removing the timestamp from underscore, so that it is ready to consume. 
    for filename in $targetFolderName*; do 

     mv -v "${filename}" ${filename%_*}.`echo "${filename}" | awk -F. '{print $2}'` 

    done